A drilled shaft is shown in Figure P10.1. Determine the net allowable point bearing capacity. Given Ye = 15.6 kN/m³ Ys = 17.6 kN/m³ 6' = 35° D, = 2 m D = 1.2 m Lj = 6 m L = 3 m Factor of safety C, = 35 kN/m² 3 L=L, Q,-Σα"c,p ΔL (10.37) L=0 atmospheric pressure = 100 kN/m² (~2000 lb/ft?). So, conservatively, we may assume that where Pa = a* = 0.4 (10.39)

A drilled shaft is shown in Figure P10.1. Determine the net allowable point bearing capacity. Given Ye = 15.6 kN/m³ Ys = 17.6 kN/m³ 6' = 35° D, = 2 m D = 1.2 m Lj = 6 m L = 3 m Factor of safety C, = 35 kN/m² 3 L=L, Q,-Σα"c,p ΔL (10.37) L=0 atmospheric pressure = 100 kN/m² (~2000 lb/ft?). So, conservatively, we may assume that where Pa = a* = 0.4 (10.39)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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