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A drilled shaft is shown in Figure P10.1. Determine the net allowable point bearing capacity. Given Ye = 15.6 kN/m³ Ys = 17.6 kN/m³ 6' = 35° D, = 2 m D = 1.2 m Lj = 6 m L = 3 m Factor of safety C, = 35 kN/m² 3 L=L, Q,-Σα"c,p ΔL (10.37) L=0 atmospheric pressure = 100 kN/m² (~2000 lb/ft?). So, conservatively, we may assume that where Pa = a* = 0.4 (10.39)

A drilled shaft is shown in Figure P10.1. Determine the net allowable point bearing capacity. Given Ye = 15.6 kN/m³ Ys = 17.6 kN/m³ 6' = 35° D, = 2 m D = 1.2 m Lj = 6 m L = 3 m Factor of safety C, = 35 kN/m² 3 L=L, Q,-Σα"c,p ΔL (10.37) L=0 atmospheric pressure = 100 kN/m² (~2000 lb/ft?). So, conservatively, we may assume that where Pa = a* = 0.4 (10.39)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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For the drilled shaft described in Problem 10.1, what skin resistance would develop in the top 6 m, which are in clay ?

A drilled shaft is shown in Figure P10.1. Determine the net allowable point bearing capacity. Given Ye = 15.6 kN/m³ Ys = 17.6 kN/m³ 6' = 35° D, = 2 m D = 1.2 m Lj = 6 m L = 3 m Factor of safety C, = 35 kN/m² 3
Transcribed Image Text:A drilled shaft is shown in Figure P10.1. Determine the net allowable point bearing capacity. Given Ye = 15.6 kN/m³ Ys = 17.6 kN/m³ 6' = 35° D, = 2 m D = 1.2 m Lj = 6 m L = 3 m Factor of safety C, = 35 kN/m² 3
L=L, Q,-Σα"c,p ΔL (10.37) L=0 atmospheric pressure = 100 kN/m² (~2000 lb/ft?). So, conservatively, we may assume that where Pa = a* = 0.4 (10.39)
Transcribed Image Text:L=L, Q,-Σα"c,p ΔL (10.37) L=0 atmospheric pressure = 100 kN/m² (~2000 lb/ft?). So, conservatively, we may assume that where Pa = a* = 0.4 (10.39)
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