A drilled shaft is constructed in a uniform clay layer of 40 ft. and tipped in a uniform,dense sand layer with N60 of 30. The drilled shaft has a diameter of 3 ft. and embeddedlength is 40 ft. Assume a total unit weight of 125 pcf for clay and 120 pcf for sand. Thewater table is at a depth of 15-ft. The unit weight of clay below water table is 125 pcf aswell. The clay layer has undrained shear strength of 2 ksf. Assume depth of zone ofseasonal moisture change to be 5-ft. Find the ultimate load capacity of the drilled shaft.Use alpha method for clay and beta method for sand.Clayy=Ysat=125 pcfc,=2 ksf15 ftWater table40 ftDense sand: N=30; Ysat=120 pcf

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A drilled shaft is constructed in a uniform clay layer of 40 ft. and tipped in a uniform, dense sand layer with N60 of 30. The drilled shaft has a diameter of 3 ft. and embedded length is 40 ft. Assume a total unit weight of 125 pcf for clay and 120 pcf for sand. The water table is at a depth of 15-ft. The unit weight of clay below water table is 125 pef as well. The clay layer has undrained shear strength of 2 ksf. Assume depth of zone of seasonal moisture change to be 5-ft. Find the ultimate load capacity of the drilled shaft. Use alpha method for clay and beta method for sand. Clay y= Ysat=125 pcf c,=2 ksf 15 ft Water table 40 ft Dense sand: N0=30; Ysat=120 pcf

A drilled shaft is constructed in a uniform clay layer of 40 ft. and tipped in a uniform, dense sand layer with N60 of 30. The drilled shaft has a diameter of 3 ft. and embedded length is 40 ft. Assume a total unit weight of 125 pcf for clay and 120 pcf for sand. The water table is at a depth of 15-ft. The unit weight of clay below water table is 125 pef as well. The clay layer has undrained shear strength of 2 ksf. Assume depth of zone of seasonal moisture change to be 5-ft. Find the ultimate load capacity of the drilled shaft. Use alpha method for clay and beta method for sand. Clay y= Ysat=125 pcf c,=2 ksf 15 ft Water table 40 ft Dense sand: N0=30; Ysat=120 pcf

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Load and resistance factor design

Load and resistance factors design (LRFD), also known as Limit state design (LSD), refers to the design method used in building engineering. A boundary condition is a condition of a structure where it can no longer meet the relevant design requirements. The condition may refer to the load level or other actions on the structure, while the terms refer to the integrity of the structure, suitability for use, durability, or other design requirements. A structure designed for LRFD is limited to keeping track of all possible actions during its design time and is always ready for use, with the appropriate level of reliability in each boundary condition. LRFD-based construction codes clearly define the appropriate levels of reliability in their instructions.

Question

A drilled shaft is constructed in a uniform clay layer of 40 ft. and tipped in a uniform,
dense sand layer with N60 of 30. The drilled shaft has a diameter of 3 ft. and embedded
length is 40 ft. Assume a total unit weight of 125 pcf for clay and 120 pcf for sand. The
water table is at a depth of 15-ft. The unit weight of clay below water table is 125 pcf as
well. The clay layer has undrained shear strength of 2 ksf. Assume depth of zone of
seasonal moisture change to be 5-ft. Find the ultimate load capacity of the drilled shaft.
Use alpha method for clay and beta method for sand.
Clay
y=Ysat=125 pcf
c,=2 ksf
15 ft
Water table
40 ft
Dense sand: N=30; Ysat=120 pcf

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