A double-pane window consists of two layers of glass separated by an evacuated space a) For specified indoor and outdoor temperatures, the rate of heat loss through the window and the temperature of the inner surface of the window shall be determined; b) Plot heat loss rate as a function of evacuated space thickness. Нурotheses • Heat transfer through the window is in RP since indoor and outdoor temperatures remain constant over time. Heat transfer is one-dimensional, as any significant temperature gradients will exist from the inside to the outside.

A double-pane window consists of two layers of glass separated by an evacuated space a) For specified indoor and outdoor temperatures, the rate of heat loss through the window and the temperature of the inner surface of the window shall be determined; b) Plot heat loss rate as a function of evacuated space thickness. Нурotheses • Heat transfer through the window is in RP since indoor and outdoor temperatures remain constant over time. Heat transfer is one-dimensional, as any significant temperature gradients will exist from the inside to the outside.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

A double-pane window consists of two layers of glass separated by an evacuated space.
a) For specified indoor and outdoor temperatures, the rate of heat loss through the
window and the temperature of the inner surface of the window shall be determined;
b) Plot heat loss rate as a function of evacuated space thickness.
Нуpotheses
Heat transfer through the window is in RP since indoor and outdoor
temperatures remain constant over time.
Heat transfer is one-dimensional, as any significant temperature gradients will
exist from the inside to the outside.
The thermal conductivity of glass is constant.
Radiation heat transfer is negligible.
Property:
The thermal conductivity of the glass is considered to be k= 0.78 W/m-°C.
Data:
Area= (1.2x2) m?
L glass = 3 mm
L air = 12 mm
T internal = 24°C
T external = -5 °C
h internal = 10 W/m2C
h external = 25 W/ m2C

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