A double overhung impulse turbine of 85% efficiency is direct-connected to a 30-MW generator of 93% efficiency. Elevation of head water level is 832 m above sea level, elevation of tailwater level is 384 m above sea level, turbine setting is 3.7 m, velocity of flow in penstock is equal to 0.025√2gh, loss of head due to friction is 2% of gross head. Compute: a) Flow in second metre through penstock. b) Flow in second metre through turbine. c) Diameter of jet in mm if nozzle efficiency is 98%.

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A double overhung impulse turbine of 85% efficiency is direct-connected to a 30-MW generator of 93% efficiency. Elevation of head water level is 832 m above sea level, elevation of tailwater level is 384 m above sea level, turbine setting is 3.7 m, velocity of flow in penstock is equal to 0.025√2gh, loss of head due to friction is 2% of gross head. Compute:
a) Flow in second metre through penstock.
b) Flow in second metre through turbine.
c) Diameter of jet in mm if nozzle efficiency is 98%.
d) Diameter of wheel in metres.
e) Rotative speed in rpm if peripheral speed is 0.45√2gh.
f) Specific speed of turbine in rpm.

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A double overhung impulse turbine of 85% efficiency is direct-connected to a 30-MW generator of 93%
efficiency. Elevation of head water level is 832 m above sea level, elevation of tailwater level is 384 m above
sea level, turbine setting is 3.7 m, velocity of flow in penstock is equal to 0.025v2gh, loss of head due to
friction is 2% of gross head. Compute:
a) Flow in second metre through penstock.
b) Flow in second metre through turbine.
c) Diameter of jet in mm if nozzle efficiency is 98%.
d) Diameter of wheel in metres.
e) Rotative speed in rpm if peripheral speed is 0.45v2gh.
f) Specific speed of turbine in rpm.
Transcribed Image Text:A double overhung impulse turbine of 85% efficiency is direct-connected to a 30-MW generator of 93% efficiency. Elevation of head water level is 832 m above sea level, elevation of tailwater level is 384 m above sea level, turbine setting is 3.7 m, velocity of flow in penstock is equal to 0.025v2gh, loss of head due to friction is 2% of gross head. Compute: a) Flow in second metre through penstock. b) Flow in second metre through turbine. c) Diameter of jet in mm if nozzle efficiency is 98%. d) Diameter of wheel in metres. e) Rotative speed in rpm if peripheral speed is 0.45v2gh. f) Specific speed of turbine in rpm.
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d) Diameter of wheel in metres.
e) Rotative speed in rpm if peripheral speed is 0.45√2gh.
f) Specific speed of turbine in rpm.

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