Design of steel structure.. A double cover butt riveted joint is used toconnect two flat plates of 200 mm width and 14 mmthickness as show in the figure. There are twelvepower driven rivets of 20 mm diameter at a pitch of50 mm in both directions on either side of the plate.Two cover plates of 10 mm thickness are used. Thecapacity of the joint in tension consideringbearing and shear ONLY, with permissible bearingand shear stresses as 300 MPa respectively is50mm+50mm50mm50mm50mm 50mm 50mm1111111111111111111111

Given data- A double cover butt riveted joint- Two flat plates of 200 mm width, b=200 mm, Thickness…

Answered: A double cover butt riveted joint is…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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4. Six rivets are used in the connection shown in the figure. If both P= 50 kN, what is the minimum diameter P- 50 rivet is necessary so as not to exceed the 70MPA allow shearing stress? What thickness of plate is required so as not to exceed a bearing stress of 140 MPa? 80 mm 80 mm Ps so 100 mm
Six rivets are used in the connection shown in the figure. If both P=50KN, what is the minimum diameter rivet is necessary so as not exceed the 70MPa allow shearing stress? What thickness of plate is required so as not exceed a bearing stress of 140MPA? p= 50 80 mm 80 mm 100 mm
REVISED PROBLEM: M3 HW 4 4. Six rivets are used in the connection shown in the figure. If both P = 50 kN, what is the minimum diameter P- 50 rivet is necessary so as not to exceed the 70MPA allow shearing stress? What thickness of plate is required so as not to exceed a bearing stress of 140 MPa? 80 mm 80 mm Peso 100 m
Given the following allowable stresses:• 50 MPa for shear in rivets• 100 MPa for bearing between a plate and a rivet• 80 MPa for tension in the platesDetermine the maximum load P that can be applied to the lap joint connected bythree – 16 mm diameter rivets. Note: Draw its FBD
A square hollow steel strut if thickness 10mm is pin connected to two connector plates of thickness, 12mm. The connector plates are welded to the base plate of thickness, 12mm. The base plate is fastened to te concrete base by 4-16mm diameter anchor bolts. The diameter of the pin is 16mm. Which of the following most nearly gives the shearing stress in the anchor bolts? Choices 150.00 MPa 59.68 MPa 51.69 MPa 119.37 MPa
One plate of size 100 mm x 12 mm is lap joined to another plate of size 200 mm x 12 mm by fillet weld of size 10 mm. Lap length is 100 mm. Fillet weld is provided on all the three sides of the smaller plate. Determine the maximum axial tension the joint could carry. Assume the plates are of mild steel of grade 250 N/mm?.
The gusset is riveted to a larger plate by 4 – 22mm rivets in single shear arranged andloaded as shown. Calculate the stress in the most heavily loaded rivet.
The five-bolt connection shown must support an applied load of P = 371 kN. If the average shear stress in the bolts must be limited to 174 MPa, determine the minimum bolt diameter that may be used in the connection. Answer: d = i mm.
7. The bracket shown is welded on one side of a steel column with 800mm of 6mm fillet weld. Determine the maximum shear stress on the weld. If the allowable stress si 400 MPa what is the allowable load that the connection can carry? 44 kN 300 mm F.W. ON NEAR SIDE F.W. ON FAR SIDE F.W. ON FAR SIDE F.W. ON NEAR SIDE 200 mm 200 mm
For the given riveted connection shown, having the allowable stresses: Fy = 248 MPa Fy = 150 MPa (shear stress) Tensile stress=0.60 Fy Bearing stress = 1.35 Fy Rivet hole has a diameter 2mm greater than the rivet diameter. The main plate has a width of 300mm and a thickness of 20mm. Determine the diameter of rivets such the shear capacity of the rivets is equal to its bearing capacity. Also, compute the maximum value of P so as not to exceed the allowable tensile stress of plates. P- O JAK O O 300 mm -P/2 -P/2
For the given riveted connection shown, having the allowable stresses: Fy = 248 MPa Fy = 150 MPa (shear stress) Tensile stress = 0.60 Fy Bearing stress = 1.35 Fy Rivet hole has a diameter 2mm greater than the rivet diameter. The main plate has a width of 300mm and a thickness of 20mm. Determine the diameter of rivets such the shear capacity of the rivets is equal to its bearing capacity. Also, compute the maximum value of P so as not to exceed the allowable tensile stress of plates. 300 mm t/2 -P/2 P- -P/2
The five-bolt connection shown must support an applied load of P = 330 kN. If the average shear stress in the bolts must be limited to 255 MPa, determine the minimum bolt diameter that may be used in the connection.

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