A doctor wants to estimate the mean length of hospital stay of covid-19 patients with a 98% confidence interval. Estimate the sample size required so that margin of error does not exceed 2 days. Assume population standard deviation o 6 days.

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**Problem Statement: Estimating Sample Size for Hospital Stay Analysis**

A doctor aims to determine the average length of hospital stay for COVID-19 patients, ensuring a 98% confidence level in the results. The goal is to figure out the necessary sample size so that the margin of error does not exceed 2 days. The standard deviation of the population is assumed to be \( \sigma = 6 \) days. 

**Solution Approach:**

To solve this problem, you will need to use the formula for determining the sample size \( n \) for estimating a mean with a given margin of error \( E \):

\[
n = \left( \frac{Z \cdot \sigma}{E} \right)^2
\]

Where:
- \( Z \) is the Z-value corresponding to the desired confidence level (98% confidence level).
- \( \sigma \) is the population standard deviation (6 days).
- \( E \) is the margin of error (2 days).

**Steps:**

1. Determine the Z-value for a 98% confidence interval.
2. Substitute the values into the formula to calculate \( n \).

By following these steps, you will compute the appropriate sample size required to estimate the mean hospital stay length accurately within the specified margin of error.
Transcribed Image Text:**Problem Statement: Estimating Sample Size for Hospital Stay Analysis** A doctor aims to determine the average length of hospital stay for COVID-19 patients, ensuring a 98% confidence level in the results. The goal is to figure out the necessary sample size so that the margin of error does not exceed 2 days. The standard deviation of the population is assumed to be \( \sigma = 6 \) days. **Solution Approach:** To solve this problem, you will need to use the formula for determining the sample size \( n \) for estimating a mean with a given margin of error \( E \): \[ n = \left( \frac{Z \cdot \sigma}{E} \right)^2 \] Where: - \( Z \) is the Z-value corresponding to the desired confidence level (98% confidence level). - \( \sigma \) is the population standard deviation (6 days). - \( E \) is the margin of error (2 days). **Steps:** 1. Determine the Z-value for a 98% confidence interval. 2. Substitute the values into the formula to calculate \( n \). By following these steps, you will compute the appropriate sample size required to estimate the mean hospital stay length accurately within the specified margin of error.
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The provided information are:

Population standard deviation(σ)=6Margin of error (E) =2Confidence level = 98%

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