A distribution of values is normal with a mean of 642.9 and a standard deviation of 39.8. Find the probability that a randomly selected value is between 526.3 and 746.8. P(526.3 < X < 746.8) = * 4 decimal places. *Note: all z-scores must be rounded to the nearest hundredth.
A distribution of values is normal with a mean of 642.9 and a standard deviation of 39.8. Find the probability that a randomly selected value is between 526.3 and 746.8. P(526.3 < X < 746.8) = * 4 decimal places. *Note: all z-scores must be rounded to the nearest hundredth.
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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A distribution of values is normal with a mean of 642.9 and a standard deviation of 39.8.
Find theprobability that a randomly selected value is between 526.3 and 746.8.
P(526.3 < X < 746.8) =
Find the
P(526.3 < X < 746.8) =
* 4 decimal places. *Note: all z-scores must be rounded to the nearest hundredth.
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