A distribution of values is normal with a mean of 19 deviation of 45.2. Find the probability that a randomly selected value P(X > 331) =|
A distribution of values is normal with a mean of 19 deviation of 45.2. Find the probability that a randomly selected value P(X > 331) =|
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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![A distribution of values is normal with a mean of 199.9 and a standard
deviation of 45.2.
Find the probability that a randomly selected value is greater than 331.
P(X > 331) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded to 3 decimal places are
accepted.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4e14fd6b-c133-41dc-b118-ac1447875d77%2F5b8dc706-bfc4-424d-a379-5f21793a5ff8%2Fxhmi9w7_processed.png&w=3840&q=75)
Transcribed Image Text:A distribution of values is normal with a mean of 199.9 and a standard
deviation of 45.2.
Find the probability that a randomly selected value is greater than 331.
P(X > 331) =
Enter your answer as a number accurate to 4 decimal places. Answers
obtained using exact z-scores or z-scores rounded to 3 decimal places are
accepted.
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