A distribution of values is normal with a mean of 19 deviation of 45.2. Find the probability that a randomly selected value P(X > 331) =|
Q: Assume that adults have IQ scores that are normally distributed with a mean of μ=100 and a standard…
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Q: Assume that adults have IQ scores that are normally distributed with a mean of mu equals 105 and…
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A: According to the provided information, Mean (μ) = 104.7 Standard Deviation (σ) = 15.7
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A: From the provided information, Mean (µ) = 137.2 Standard deviation (σ) = 46.9 X~N (137.2, 46.9)
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A: Given: μ=100.6, σ=19.5 The corresponding z-value needed to be computed is:
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Q: Assume that adults have IQ scores that are normally distributed with a mean of μ=105 and a standard…
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A: Given: Z ~ N (0, 1) P (- 0.9 < z < b) = 0.5607
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- Assume that adults have IQ scores that are normally distributed with a mean of 104.3 and a standard deviation of 15.6. Find the probability that a randomly selected adult has an 1Q greater than 125.0. (Hint: Draw a graph.) The probability that a randomly selected adult from this group has an 1Q greater than 125.0 is (Round to four decimal places as needed.)Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score greater than 0.33 a. The probability is (Round to four decimal places as needed.)Previously, De Anza's statistics students estimated that the amount of change daytime statistics students carry is exponentially distributed with a mean of $0.88. Suppose that we randomly pick 25 daytime statistics students. Find the probability that an individual had between $0.80 and $1.00. Graph the situation, and shade in the area to be determined.
- Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1.If P(-b<z<b)=0.9716, find b.Assume that a randomly selected subject is given a bone density test. Those test scores are normally distributed with a mean of 0 and a standard deviation of 1. Draw a graph and find the probability of a bone density test score between -1.96 and 1.96. The probability is _____ (Round to four decimal places as needed.)Assume that adults have IQ scores that are normally distributed with a mean of 104.9 and a standard deviation of 16. Find the probability that a randomly selected adult has an IQ greater than 132.8. (Hint: Draw a graph.) The probability that a randomly selected adult from this group has an IQ greater than 132.8 is (Round to four decimal places as needed.)
- Find the F-test statistic to test the claim that the population variances are equal. Both distributions are normal. The standard deviation of the first sample is 3.96014.5373 is the standard deviation of the second sample.The GPA of all students in rolled at a large university have approximately normal distribution with A mean of 3.02 and a standard deviation of 0.29. Find the probability that the mean GPA of a random sample of 20 students selected from this university is 2.93 to 3.10. Round your answer to four decimal placesAssume that a randomly selected subject is given a bone density test. These test scores are normally distributed with a mean of 0 and a standard deviation of 1. Find the probability that a given score is less than -0.71.
- The probability that a trainee will remain with a company is 0.6. the probability that am employee earnsbmore than k10,000 per month is 0.5. the probability that an employee who is a trainee remained with the company or who earns more than k10,000 per month is 0.7. what is the probability that an employee earns more than k10,000 per month given that he is a trainee who stayed with the companyA normal distribution has a mean of 147 and a standard deviation of 4. Find the z-score for a data value of 133. Round to two decimal placesSuppose the mean cholesterol levels of women age 45-59 is 5.2 mmol/l and the standard deviation is 0.7 mmol/l. Assume that cholesterol levels are normally distributed. Find the probability that a woman age 45-59 has a cholesterol level above 6.1 mmol/l (considered a high level). Round to four decimal places.P(x > 6.1) = Suppose doctors decide to test the woman’s cholesterol level again and average the two values. Find the probability that this woman’s mean cholesterol level for the two tests is above 6.1 mmol/l. Round to four decimal places.P(x̄ > 6.1) = Suppose doctors being very conservative decide to test the woman’s cholesterol level a third time and average the three values. Find the probability that this woman’s mean cholesterol level for the three tests is above 6.1 mmol/l. Round to four decimal places.P(x̄ > 6.1) =