A disk between vertebrae in the spine is subjected to a shearing force of 625 N. Find its shear deformation, taking it to have a shear modulus of 1.30 x 10° N/m2. The disk is equivalent to a solid cylinder 0.550 cm high and 2.50 cm in diameter. Question Credit: OpenStax College Physics shear deformation: m
A disk between vertebrae in the spine is subjected to a shearing force of 625 N. Find its shear deformation, taking it to have a shear modulus of 1.30 x 10° N/m2. The disk is equivalent to a solid cylinder 0.550 cm high and 2.50 cm in diameter. Question Credit: OpenStax College Physics shear deformation: m
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A disk between vertebrae in the spine is subjected to a shearing force of 625 N. Find its shear deformation, taking it to have a
shear modulus of 1.30 x 10° N/m². The disk is equivalent to a solid cylinder 0.550 cm high and 2.50 cm in diameter.
Question Credit: OpenStax College Physics
shear deformation:
m

Transcribed Image Text:The large block shown is x = 72 cm wide, y = 54 cm long,
and z = 9.0 cm high. This block is passing through air
(density of air p =
1.43 kg/m) at a speed of v = 7.98 m/s.
Find the drag force Fa1 acting on the block when it has the
velocity v1 and a drag coefficient I
0.902.
Fa,1
N
Find the drag force Fa2 acting on the block when it has the
velocity v2 with a drag coefficient I = 0.992.
Fa,2
Find the drag force Fa.3 acting on the block when it has the
velocity vz with a drag coefficient I
= 1.17.
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