A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by2 = (0, 4750 295,0)mThe charges making up the dipole are 9₁ = +4 nC and 92 = -4 nC, and the dipole separation is s = 8 mm (see figure below). What is the potential difference along a path starting at location P₁ = (0, 0.04, 0) mand ending at location P₂ = (0, 0.05, 0) m?0.1152x VP₂*P₁

Given, Charges, q1=4nCq2=-4nC Distance between charges, s=8mms=8×10-3m Location,…

A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by # = (0, 4750 25,0) m The charges making up the dipole are 91 = +4 nC and 92 = -4 nC, and the dipole separation is s= 8 mm (see figure below). What is the potential difference along a path starting at location P₁ = (0, 0.04, 0) m and ending at location P₂ = (0, 0.05, 0) m? 0.1152 x V * P₂ P₁ 92

A dipole is centered at the origin, with its axis along the y axis, so that at locations on the y axis, the electric field due to the dipole is given by # = (0, 4750 25,0) m The charges making up the dipole are 91 = +4 nC and 92 = -4 nC, and the dipole separation is s= 8 mm (see figure below). What is the potential difference along a path starting at location P₁ = (0, 0.04, 0) m and ending at location P₂ = (0, 0.05, 0) m? 0.1152 x V * P₂ P₁ 92

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