A diode is an electronic device that let the current flow in only one direction, that is the current through the diode is I=V/R (R is the diode resistance, a constant) if V > 0 and I=0 if V≤0. The diode is excited by an alternative voltage V(t) = cos(wot). (a) Sketch the diode response I(t) as a function of t. Indicate clearly the minimum values +to for which I(t) drops to zero. (b) Calculate the Fourier transform F(w) of the diode response. Hint: because the function is periodic, you only have to calculate the integral between ±to. (c) Schematically plot F(w) versus w. (d) A Lock-in amplifier is an electronic setup that can measure the response at integer frequency of the excitation frequency. What would a Lock-in measure at f = 2fo? (wo = 2nfo).

Modern Physics
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Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
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Chapter12: The Solid State
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A diode is an electronic device that let the current flow in only one direction, that is the current
through the diode is I=V/R (R is the diode resistance, a constant) if V > 0 and I=0 if V≤0. The
diode is excited by an alternative voltage V(t) = cos(wot).
(a) Sketch the diode response I(t) as a function of t. Indicate clearly the minimum values +to
for which I(t) drops to zero.
(b) Calculate the Fourier transform F(w) of the diode response. Hint: because the function is
periodic, you only have to calculate the integral between ±to.
(c) Schematically plot F(w) versus w.
(d) A Lock-in amplifier is an electronic setup that can measure the response at integer
frequency of the excitation frequency. What would a Lock-in measure at f = 2fo?
(wo = 2nfo).
Transcribed Image Text:A diode is an electronic device that let the current flow in only one direction, that is the current through the diode is I=V/R (R is the diode resistance, a constant) if V > 0 and I=0 if V≤0. The diode is excited by an alternative voltage V(t) = cos(wot). (a) Sketch the diode response I(t) as a function of t. Indicate clearly the minimum values +to for which I(t) drops to zero. (b) Calculate the Fourier transform F(w) of the diode response. Hint: because the function is periodic, you only have to calculate the integral between ±to. (c) Schematically plot F(w) versus w. (d) A Lock-in amplifier is an electronic setup that can measure the response at integer frequency of the excitation frequency. What would a Lock-in measure at f = 2fo? (wo = 2nfo).
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