A digital computer has a memory unit with 32 bits per word. The instruction set consists of 127 different operations. All instructions have an operation code part (opcode), and an address part (allowing for only one address). Each instruction is stored in one word of memory. How many bits are needed for the opcode? ________ How many bits are left for the address part of the instruction? _______
A digital computer has a memory unit with 32 bits per word. The instruction set consists of 127 different operations. All instructions have an operation code part (opcode), and an address part (allowing for only one address). Each instruction is stored in one word of memory. How many bits are needed for the opcode? ________ How many bits are left for the address part of the instruction? _______
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
- A digital computer has a memory unit with 32 bits per word. The instruction set consists of 127 different operations. All instructions have an operation code part (opcode), and an address part (allowing for only one address). Each instruction is stored in one word of memory.
- How many bits are needed for the opcode? ________
- How many bits are left for the address part of the instruction? _______
- What is the maximum allowable size for memory? _________
Expert Solution
Step 1
1)7 bits, because 2^7-1 = 127 possible opcodes.
2) 25 bits, because 32 - 7 = 25.
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