A differentiable function has the value y(2) = 4 and the derivative value y'(2) = -3. Approximate the value of y(2.1). O 3.7 O 3.75 O 3.8 O 3.85 17 18

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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### Problem Statement

A differentiable function has the value \( y(2) = 4 \) and the derivative value \( y'(2) = -3 \). Approximate the value of \( y(2.1) \).

### Answer Options

- 3.7
- 3.75
- 3.8
- 3.85

### Explanation:

To approximate \( y(2.1) \), we can use the linear approximation formula:

\[ y(x) \approx y(a) + y'(a)(x - a) \]

Substitute \( a = 2 \) and \( x = 2.1 \):

\[ y(2.1) \approx y(2) + y'(2)(2.1 - 2) \]

Plug in the given values:

\[ y(2.1) \approx 4 + (-3)(0.1) \]
\[ y(2.1) \approx 4 - 0.3 \]
\[ y(2.1) \approx 3.7 \]

Thus, the approximate value of \( y(2.1) \) is 3.7.
Transcribed Image Text:### Problem Statement A differentiable function has the value \( y(2) = 4 \) and the derivative value \( y'(2) = -3 \). Approximate the value of \( y(2.1) \). ### Answer Options - 3.7 - 3.75 - 3.8 - 3.85 ### Explanation: To approximate \( y(2.1) \), we can use the linear approximation formula: \[ y(x) \approx y(a) + y'(a)(x - a) \] Substitute \( a = 2 \) and \( x = 2.1 \): \[ y(2.1) \approx y(2) + y'(2)(2.1 - 2) \] Plug in the given values: \[ y(2.1) \approx 4 + (-3)(0.1) \] \[ y(2.1) \approx 4 - 0.3 \] \[ y(2.1) \approx 3.7 \] Thus, the approximate value of \( y(2.1) \) is 3.7.
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