A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignite the fuel occurs because the pistons compress the air in the cylinders. Suppose air at an initial temperature of 26.9 °C is compressed adiabatically to a temperature of 671 °C. Assume the air to be an ideal gas for which =. Find the compression ratio, which is the ratio of the initial volume to the final volume. Number Units
A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignite the fuel occurs because the pistons compress the air in the cylinders. Suppose air at an initial temperature of 26.9 °C is compressed adiabatically to a temperature of 671 °C. Assume the air to be an ideal gas for which =. Find the compression ratio, which is the ratio of the initial volume to the final volume. Number Units
College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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The second image shows how I worked this out. I don't see how I'm getting this wrong. Thank you for your help.
![The expression provided is a complex mathematical equation, which is evaluated as follows:
\[
\frac{671 + 273 \left( \frac{1}{\frac{7}{5} - 1} \right)}{26.9 + 273} = 4.513171057
\]
**Explanation:**
1. **Numerator:**
- Starts with the addition 671 + 273.
- Inside the parentheses, there is a fraction: \(\frac{1}{\frac{7}{5} - 1}\).
- The inner fraction \(\frac{7}{5} - 1\) needs to be simplified:
- Convert 1 to a fraction with denominator 5: \(\frac{5}{5}\).
- Subtract to get \(\frac{7}{5} - \frac{5}{5} = \frac{2}{5}\).
- The final inner fraction becomes \(\frac{1}{\frac{2}{5}}\), which is the same as \(\frac{5}{2}\) when inverted.
- Thus, complete the multiplication: \(273 \times \frac{5}{2}\).
2. **Denominator:**
- The simple addition of 26.9 + 273.
3. **Result:**
- The evaluated expression equals 4.513171057.
This expression involves arithmetic operations and fractional transformations. It combines addition, multiplication, and the simplification of fractions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd261088c-f753-45e4-ae14-7adbaf3c257c%2Ff146a47e-5475-4521-9175-1f2ebd3e9251%2Fazf5k0r_processed.png&w=3840&q=75)
Transcribed Image Text:The expression provided is a complex mathematical equation, which is evaluated as follows:
\[
\frac{671 + 273 \left( \frac{1}{\frac{7}{5} - 1} \right)}{26.9 + 273} = 4.513171057
\]
**Explanation:**
1. **Numerator:**
- Starts with the addition 671 + 273.
- Inside the parentheses, there is a fraction: \(\frac{1}{\frac{7}{5} - 1}\).
- The inner fraction \(\frac{7}{5} - 1\) needs to be simplified:
- Convert 1 to a fraction with denominator 5: \(\frac{5}{5}\).
- Subtract to get \(\frac{7}{5} - \frac{5}{5} = \frac{2}{5}\).
- The final inner fraction becomes \(\frac{1}{\frac{2}{5}}\), which is the same as \(\frac{5}{2}\) when inverted.
- Thus, complete the multiplication: \(273 \times \frac{5}{2}\).
2. **Denominator:**
- The simple addition of 26.9 + 273.
3. **Result:**
- The evaluated expression equals 4.513171057.
This expression involves arithmetic operations and fractional transformations. It combines addition, multiplication, and the simplification of fractions.
Transcribed Image Text:A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignite the fuel occurs because the pistons compress the air in the cylinders. Suppose air at an initial temperature of 26.9 °C is compressed adiabatically to a temperature of 671 °C. Assume the air to be an ideal gas for which \( \gamma = \frac{7}{5} \). Find the compression ratio, which is the ratio of the initial volume to the final volume.
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