15. What is the direction of that force on the proton? Ans: B c. Into b. Down a. Up d. Left 16. If the currents remain the same as found in above, what will be the magnitude of the magnetic field for Point A (remember, this will be the result of both wires (don't forget to take account the directions of each B-field from each wire)? Ans: B |A. 1.66x10-$T B. 2.00x10°T |С. 3.00х10%T D. 4.00x10$T 17. What will be the direction of the B-field at Point A? Ans: B a. Into the page b. Out of the page 18. If a third current carrying wire is laid parallel to the original wires carrying a 5A current downward and passing through Point A, what will be the force per unit length on that wire (remember, there is a formula for the force on a current-carrying wire immersed in a magnetic field)? Ans: A A. 1.00x10“N В. 2.00х10-N C. 3.00x10“N D. 4.00x104N

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Chapter1: Units, Trigonometry. And Vectors
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Please show the detailed solution for part 15,16,17 and 18. Please give detailed answer, Full Question is given in the images attached, Thanks!

 

Ampere's Law was used to show that the magnitude of the magnetic field a distance R from a long, thin wire
carrying current I is given by:
В
27R
ILeft
Iright
A right hand rule can be used to determine the direction of this
magnetic field.
d
A
C
Two parallel wires, separated by a distance of 20 cm, are carrying currents. The
lefthand current, Iet, Wire carries a current ILet = 15 A in the direction shown and
the other carries a current Iright = 25A current as shown. Point C is a distance of
10 cm to the right of the Iright current and Point A is halfway between the two
wires. (Show your work below and on the following page. Be sure to label to
which section the work belongs).
Color the left hand wire red and color the right hand wire green. Then, on the diagram, using
correspondingly colored ® and • to represent “into" and “out of" the page, respectively, show the
magnetic field directions for each wire in all the regions left, right, and in-between the wires.
10. What is the magnitude of the B-field at Point C due to Iright? Ans: C
А. 1.66х10-5T
D. 4.00x10$T
B. 2.00x10ST
| C. 5.00x10-$T
11. What is the magnitude of the B-Field at Point C due to ILeh?
B. 2.00x10³T
Ans: A
|A. 1.00x10-$T
C. 3.00x10-³T
D. 4.00x10-°T
12. What is the total magnetic field at Point C (both magnitude and direction must be correct for credit)?
Ans: C
a. 1.34x10$ T
b. 7.00x10$ T
c. 6.00x105 T
d. 0 T
13. What is the DIRECTION of the total magnetic field at Point C? Ans: A
a. Into page
b. Left
c. Right
d. Out of page
Transcribed Image Text:Ampere's Law was used to show that the magnitude of the magnetic field a distance R from a long, thin wire carrying current I is given by: В 27R ILeft Iright A right hand rule can be used to determine the direction of this magnetic field. d A C Two parallel wires, separated by a distance of 20 cm, are carrying currents. The lefthand current, Iet, Wire carries a current ILet = 15 A in the direction shown and the other carries a current Iright = 25A current as shown. Point C is a distance of 10 cm to the right of the Iright current and Point A is halfway between the two wires. (Show your work below and on the following page. Be sure to label to which section the work belongs). Color the left hand wire red and color the right hand wire green. Then, on the diagram, using correspondingly colored ® and • to represent “into" and “out of" the page, respectively, show the magnetic field directions for each wire in all the regions left, right, and in-between the wires. 10. What is the magnitude of the B-field at Point C due to Iright? Ans: C А. 1.66х10-5T D. 4.00x10$T B. 2.00x10ST | C. 5.00x10-$T 11. What is the magnitude of the B-Field at Point C due to ILeh? B. 2.00x10³T Ans: A |A. 1.00x10-$T C. 3.00x10-³T D. 4.00x10-°T 12. What is the total magnetic field at Point C (both magnitude and direction must be correct for credit)? Ans: C a. 1.34x10$ T b. 7.00x10$ T c. 6.00x105 T d. 0 T 13. What is the DIRECTION of the total magnetic field at Point C? Ans: A a. Into page b. Left c. Right d. Out of page
15. What is the direction of that force on the proton? Ans: B
c. Into
b. Down
a. Up
d. Left
16. If the currents remain the same as found in above, what will be the magnitude of the magnetic field
for Point A (remember, this will be the result of both wires (don't forget to take account the
directions of each B-field from each wire)? Ans: B
А. 1.66х105T
B. 2.00x10-°T
|С. 3.00х105T
D. 4.00x10-ST
17. What will be the direction of the B-field at Point A? Ans: B
a. Into the page
b. Out of the page
18. If a third current carrying wire is laid parallel to the original wires carrying a 5A current downward
and passing through Point A, what will be the force per unit length on that wire (remember, there is a
formula for the force on a current-carrying wire immersed in a magnetic field)? Ans: A
A. 1.00x10“N
B. 2.00x10“N
|С. 3.00х10-N
D. 4.00x 10“N
Transcribed Image Text:15. What is the direction of that force on the proton? Ans: B c. Into b. Down a. Up d. Left 16. If the currents remain the same as found in above, what will be the magnitude of the magnetic field for Point A (remember, this will be the result of both wires (don't forget to take account the directions of each B-field from each wire)? Ans: B А. 1.66х105T B. 2.00x10-°T |С. 3.00х105T D. 4.00x10-ST 17. What will be the direction of the B-field at Point A? Ans: B a. Into the page b. Out of the page 18. If a third current carrying wire is laid parallel to the original wires carrying a 5A current downward and passing through Point A, what will be the force per unit length on that wire (remember, there is a formula for the force on a current-carrying wire immersed in a magnetic field)? Ans: A A. 1.00x10“N B. 2.00x10“N |С. 3.00х10-N D. 4.00x 10“N
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