A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm² , plate separation d : 9.00 mm and dielectric constant k = 3.00. The capacitor is connected to a battery that creates a constant voltage V = 7.50 V . Throughout the problem, use eo = 8.85x10¬12 C2 /N·m² .

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A dielectric-filled parallel-plate capacitor has plate area AA = 30.0 cm2cm2 , plate separation dd = 9.00 mmmm and dielectric constant kk = 3.00. The capacitor is connected to a battery that creates a constant voltage VV = 7.50 VV . Throughout the problem, use ϵ0ϵ0 = 8.85×10−12 C2/N⋅m2C2/N⋅m2 .

 

 
A dielectric-filled parallel-plate capacitor has
plate area A = 30.0 cm² , plate separation d =
%3D
9.00 mm and dielectric constant k = 3.00. The
capacitor is connected to a battery that creates
a constant voltage V = 7.50 V. Throughout the
problem, use eo = 8.85x10¬12 C2 /N·m² .
Transcribed Image Text:A dielectric-filled parallel-plate capacitor has plate area A = 30.0 cm² , plate separation d = %3D 9.00 mm and dielectric constant k = 3.00. The capacitor is connected to a battery that creates a constant voltage V = 7.50 V. Throughout the problem, use eo = 8.85x10¬12 C2 /N·m² .
Part B
The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy Uz of the capacitor at the moment when the capacitor is half-filled with the dielectric.
Express your answer numerically in joules.
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U2 =
J
Submit
Previous Answers
X Incorrect; Try Again; 2 attempts remaining
Part C
The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3.
Express your answer numerically in joules.
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U3 =
J
Submit
Part D
In the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work W is done by the external agent acting on the dielectric?
Express your answer numerically in joules.
• View Available Hint(s)
Templates Symbols undo redo reset keyboard shortcuts 'help
W =
J
Transcribed Image Text:Part B The dielectric plate is now slowly pulled out of the capacitor, which remains connected to the battery. Find the energy Uz of the capacitor at the moment when the capacitor is half-filled with the dielectric. Express your answer numerically in joules. • View Available Hint(s) Templates Symbols undo rédo reset keyboard shortcuts U2 = J Submit Previous Answers X Incorrect; Try Again; 2 attempts remaining Part C The capacitor is now disconnected from the battery, and the dielectric plate is slowly removed the rest of the way out of the capacitor. Find the new energy of the capacitor, U3. Express your answer numerically in joules. • View Available Hint(s) Templates Symbols undo rådo reset keyboard shortcuts U3 = J Submit Part D In the process of removing the remaining portion of the dielectric from the disconnected capacitor, how much work W is done by the external agent acting on the dielectric? Express your answer numerically in joules. • View Available Hint(s) Templates Symbols undo redo reset keyboard shortcuts 'help W = J
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