Conduct the following test at the a= 0.05 level of significance by determining (a) the null and alternative hypotheses, (b) the test statistic, and (c) the P-value. Assume that the samples were obtainedindependently using simple random sampling.Test whether p₁ #P2. Sample data are x₁ = 28, n₁ = 255, x₂ = 38, and n₂ = 301.(a) Determine the null and alternative hypotheses. Choose the correct answer below.O A. Ho: P₁ = 0 versus H₁: P₁ = 0OC. Ho: P₁ P2 versus H₁: P₁ P2(b) The test statistic zo is(Round to two decimal places as needed.)(c) The P-value is. (Round to three decimal places as needed.)Test the null hypothesis. Choose the correct conclusion below.OB. Ho: P₁ P2 versus H₁: P₁ P2O D. Ho: P₁P2 versus H₁: P₁ P2conclude that P₁ P2-O A. Reject the null hypothesis because there is not sufficient evidenceO B. Do not reject the null hypothesis because there is not sufficient evidence to conclude that p₁ #P2.OC. Reject the null hypothesis because there is sufficient evidence to conclude that p₁ #P₂.OD. Do not reject the null hypothesis because there is sufficient evidence to conclude that p₁ > P2-

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Answered: (a) Determine the null and alternative…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The P-value for a hypothesis test is shown. Use the P-value to decide whether to reject Ho when the level of significance is (a) a= 0.01, (b) a = 0.05, and (c) α=0.10. P=0.1123 (a) Do you reject or fail to reject Ho at the 0.01 level of significance? ve this OA. Fail to reject Ho because the P-value, 0.1123, is less than α = 0.01 OB. Reject Ho because the P-value, 0.1123, is less than α=0.01. OC. Fail to reject Ho because the P-value, 0.1123, is greater than α=0.01. OD Reject Ho because the P-value, 0.1123, is greater than a = 0.01. Get more help - Q Search 16 4- 6 17 W & J+ 00 * 90 00 f9 ( f10 Janette Z 187 x
Consider the following hypothesis test. H0: ? = 100 Ha: ? ≠ 100 A sample of 65 is used. Identify the p-value and state your conclusion for each of the following sample results. Use ? = 0.05. (a) x = 104 and s = 11.5 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) State your conclusion. Reject H0. There is sufficient evidence to conclude that ? ≠ 100.Do not reject H0. There is insufficient evidence to conclude that ? ≠ 100. Do not reject H0. There is sufficient evidence to conclude that ? ≠ 100.Reject H0. There is insufficient evidence to conclude that ? ≠ 100. (b) x = 96.5 and s = 11.0 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Reject H0. There is sufficient evidence to conclude that ? ≠ 100.Do not reject H0. There is insufficient…
Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is mu greater than 98.6 degrees F. The sample size is n equals 8 and the test statistic is t equals 1.349. P-value equals (Round to three decimal places as needed.)
A test of the hypotheses, Ho: p s 0.24 and H1: p > 0.24 is a one-tailed test two-tailed test test of two sample means test of two sample proportions
Solve the problem. A researcher conducts a hypothesis test on a population proportion. Her null and alternative hypothesis are Ho: p = 0.6 and Ha: P < 0.6. The test statistic and p-value for the test are z = -1.51 and p-value = 0.0655. For a significance level of a = 0.05, choose the correct conclusion regarding the null hypothesis. O None of these. O There is sufficient evidence to warrant rejection of the null hypothesis. There is insufficient evidence to warrant rejection of the null hypothesis. STEP 1/3 Routin We're findi answer you In the mea DIVE DEEP
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Use technology to find the P-value for the hypothesis test described below. The claim is that for a smartphone carrier's data speeds at airports, the mean is μ=13.00 Mbps. The sample size is n=28 and the test statistic is t=−1.288.
Use technology to find the P-value for the hypothesis test described below. The claim is that for 12 AM body temperatures, the mean is µ> 98.6°F. The sample size is n = 9 and the test statistic is t= 1.911. P-value = (Round to three decimal places as needed.)
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A researcher wanted to determine if carpeted rooms contain more bacteria than uncarpeted rooms. The table shows the results for the number of bacteria per cubic foot for both types of rooms. Full data set O Carpeted Uncarpeted 9.4 9.1 16 10.8 6.4 10.8 14.8 8.8 11.5 11.6 13.7 9.4 10.7 12.4 13.4 7.8 Determine whether carpeted rooms have more bacteria than uncarpeted rooms at the a = 0.05 level of significance. Normal probability plots indicate that the data are approximately normal and boxplots indicate that there are no outliers. State the null and alternative hypotheses. Let population 1 be carpeted rooms and population 2 be uncarpeted rooms. OA Ho P1 H2 B. Ho H1 F2 OC Ho H= H2
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