(a) Determine the electric field intensity E caused by a spherical cloud of electrons in free space with a volume charge density p=-P for 0≤R≤a (both P, and a are positive) and p=0 for R> a. (8%)
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Q: electric field at r = 1/2 R from the center of the sphere?
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A: (a) The magnitude of the electric field at a point above the sheets can be given by the equation,
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A: Here according to question we have to find electric field due to only infinite sheet.
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Q: A large sheet of charge has a surface charge density of 1.9 μC/m2. What is the value, in newtons…
A: The the electric field magnitude just above the sheet, far from the edges is E=σ2ε0=1.9×10-6…
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A: Given: E=αe-r/ao+βr + bohere α,β,ao,bo are constants We have to find expression for Capacitance: C
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A: Diameter of sphere=0.6m So R=radius=0.3m number of electrons=N=50millions=50000000 electrons
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A: Given, Charge density,ρ=ρ0(1-4r3) Radius,R=1 m
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A: Given Data: The diameter of the sphere is D =0.6 m. The number of electrons in N=50 million. The…
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A: Given An insulating solid sphere of radius a has a uniform bulk density ρ and a total positive…
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A: In the given question, We have to determine the value of r in metre for which the electric field is…
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A: ρ = Ar when r≤R
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A: Distance of point P, r = 2 mCharge density, λ = -5.0 x 10⁶ C/mField at P, E = ?
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A: Concept used: The electric field exists perpendicular to infinite wire and it is zero on the wire.
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Q: The charge density of a non-uniformly charged sphere of radius 1.0 m is given as: For rs1.0 m; p(r)=…
A: The charge density is given as ρr=2ρ01-8r3 The gauss law is given as ∫E.dS=qε0 The surface area of…
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Q: A charge distribution has the charge density given by p = Q{s(x– x,)– 8(x+ x, }. For this charge…
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