A desperate hiker has to think fast to help his friend who has fallen below him. Quickly, he ties m, a rope to a rock of mass m, = 3.90 x 10² kg and makes his way over the ledge (see the figure). If the coefficient of static friction between the rock and the ground is 4, = 0.283, and the mass of the hiker is m = 70.1 kg, what is the maximum mass of the friend me that the rock can hold so the hikers can then make their way up over the ledge? Assume the rope is parallel to the ground and the point where the rope passes over the ledge is frictionless. m

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**Physics Problem Solving: Maximum Mass Calculation**

In this scenario, a hiker must assist his friend who has fallen. The hiker uses a rope tied to a rock with mass \( m_r = 3.90 \times 10^2 \, \text{kg} \) to rescue his friend. The goal is to determine the maximum mass of the friend, \( m_f \), that the rock can support without slipping, allowing both hikers to safely climb over the ledge.

**Problem Parameters:**
- Coefficient of static friction (\( \mu_s \)) between the rock and the ground: 0.283
- Mass of the hiker (\( m_h \)): 70.1 kg
- The rope is assumed parallel to the ground and the ledge is frictionless where the rope passes over.

**Diagram Explanation:**
The diagram shows a rocky terrain with the following key elements:
- A large rock on top, represented as \( m_r \), which the rope is tied to.
- The hiker, mass \( m_h \), standing at the edge and leaning over the precipice.
- The friend, mass \( m_f \), hanging below supported by the rope held by the hiker.

**Calculation Objective:**
Determine \( m_f \), the maximum mass of the friend that allows for a safe rescue. Solve for \( m_f \) using static friction principles and the given data.

**Formula:**
Use the equation of static friction and Newton's laws to derive \( m_f \). Consider the maximum static frictional force that holds the rock in place.

\[ m_f = \text{...} \, \text{kg} \]

Educators can engage students in solving for \( m_f \) using these parameters and understanding the application of friction and force balance in practical scenarios.
Transcribed Image Text:**Physics Problem Solving: Maximum Mass Calculation** In this scenario, a hiker must assist his friend who has fallen. The hiker uses a rope tied to a rock with mass \( m_r = 3.90 \times 10^2 \, \text{kg} \) to rescue his friend. The goal is to determine the maximum mass of the friend, \( m_f \), that the rock can support without slipping, allowing both hikers to safely climb over the ledge. **Problem Parameters:** - Coefficient of static friction (\( \mu_s \)) between the rock and the ground: 0.283 - Mass of the hiker (\( m_h \)): 70.1 kg - The rope is assumed parallel to the ground and the ledge is frictionless where the rope passes over. **Diagram Explanation:** The diagram shows a rocky terrain with the following key elements: - A large rock on top, represented as \( m_r \), which the rope is tied to. - The hiker, mass \( m_h \), standing at the edge and leaning over the precipice. - The friend, mass \( m_f \), hanging below supported by the rope held by the hiker. **Calculation Objective:** Determine \( m_f \), the maximum mass of the friend that allows for a safe rescue. Solve for \( m_f \) using static friction principles and the given data. **Formula:** Use the equation of static friction and Newton's laws to derive \( m_f \). Consider the maximum static frictional force that holds the rock in place. \[ m_f = \text{...} \, \text{kg} \] Educators can engage students in solving for \( m_f \) using these parameters and understanding the application of friction and force balance in practical scenarios.
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