A derived random variable Y = 5X2 – 3  A random variable X with probability mass function Px(x) = 1/4 (for x =1, 2, 3, 4) and 0 elsewhere. a) Set up the CDF FY(y) in terms of CDF FY(x) b) Find the PMF PY(y) of the derived random variable Y

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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  • A derived random variable Y = 5X2 – 3 
  • A random variable X with probability mass function Px(x) = 1/4 (for x =1, 2, 3, 4) and 0 elsewhere.

a) Set up the CDF FY(y) in terms of CDF FY(x)

b) Find the PMF PY(y) of the derived random variable Y

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