A "dead" 12-Volt lead/acid storage battery has 11.30 g of PbSO4 (molar mass = 303.3 g), deposited on its electrodes. To recharge it, a "trickle charger" is attached to the Pb anode that supplies 0.260 amperes of current at a voltage of 13.0 V. Calculate how much time it would take to convert all the PbSO4 back into SO42- ions in solution. Enter your answer in hours.
A "dead" 12-Volt lead/acid storage battery has 11.30 g of PbSO4 (molar mass = 303.3 g), deposited on its electrodes. To recharge it, a "trickle charger" is attached to the Pb anode that supplies 0.260 amperes of current at a voltage of 13.0 V. Calculate how much time it would take to convert all the PbSO4 back into SO42- ions in solution. Enter your answer in hours.
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter17: Electrochemistry
Section: Chapter Questions
Problem 83QAP: A lead storage battery delivers a current of 6.00 A for one hour and 22 minutes at a voltage of 12.0...
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![A "dead" 12-Volt lead/acid storage battery has 11.30 g of PBSO4 (molar mass = 303.3 g), deposited on its
electrodes. To recharge it, a "trickle charger" is attached to the Pb anode that supplies 0.260 amperes of current
at a voltage of 13.0 V. Calculate how much time it would take to convert all the PbSO4 back into SO42- ions in
solution. Enter your answer in hours.
Submit Answer
Tries 0/99](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc7221061-cab3-4d12-b574-9340e14d2678%2Faa578a03-4bef-4750-aa50-4708cb6b5483%2F67bx7yj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A "dead" 12-Volt lead/acid storage battery has 11.30 g of PBSO4 (molar mass = 303.3 g), deposited on its
electrodes. To recharge it, a "trickle charger" is attached to the Pb anode that supplies 0.260 amperes of current
at a voltage of 13.0 V. Calculate how much time it would take to convert all the PbSO4 back into SO42- ions in
solution. Enter your answer in hours.
Submit Answer
Tries 0/99
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