A data set lists weights (Ib) of plastic discarded by households. The highest weight is 5.66 Ib, the mean of all of theweights is x= 2.173 lb, and the standard deviation of the weights is s= 1.255 lb.a. What is the difference between the weight of 5.66 lb and the mean of the weights?b. How many standard deviations is that [the difference found in part (a)]?c. Convert the weight of 5.66 lb to a z score.d. If we consider weights that convert to z scores between - 2 and 2 to be neither significantly low nor significantlyhigh, is the weight of 5.66 Ib significant?.....a. The difference isIb.

Measure of central tendency measures the central or average value of a dataset. Measured of…

Answered: A data set lists weights (Ib) of…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Identify the level of measurement of the data , and explain what is wrong with the given calculation.In a set of data , blood lead levels are represented as 1 for low , 2 for medium , and 3 for high . The average ( mean ) of the 642 blood lead levels is 1.3
Both sets of value have an average of 13. Is set A's standard deviation similar, larger, or about the same as set B's? set A: 1 2 3 23 24 25 ser B: 9 10 11 14 16 18
For a data set of the pulse rates for a sample of adult females, the lowest pulse rate is 39 beats per minute, the mean of the listed pulse rates is x = 78.0 beats per minute, and their standard deviation is s = 13.1 beats per minute. %3D a. What is the difference between the pulse rate of 39 beats per minute and the mean pulse rate of the females? b. How many standard deviations is that [the difference found in part (a)]? c. Convert the pulse rate of 39 beats per minutes to a z score. d. If we consider pulse rates that convert to z scores between - 2 and 2 to be neither significantly low nor significantly high, is the pulse rate of 39 beats per minute significant? a. The difference is beats per minute. (Type an integer or a decimal. Do not round.)
Please answer a and b
A scale is known to be "low-calibrated" in that it measures an aluminum bar to be 4 grams lower than the actual weight. If ????μold is the mean of all possible measurements of the bar using the old calibration, and ????μnew is the mean of all possible measurements of the bar using a re-calibrated scale. It is desired that ????−????=4μnew−μold=4. Consider the test ?0:????−????=4H0:μnew−μold=4 vs. ?0:????−????≠4H0:μnew−μold≠4 Sample after calibration: mean is 95.8 , SD is 4.9 and sample size is 10 Sample before calibration: mean is 89.352 , SD is 4.2 and sample size is 62 We do not know population standard deviations. What is the p-value? (Hint: best to use software, or else the Desmos Calculator for the 2 sample T and Z test)
A population of N=5 scores has a mean of μ=8. If one score with a value of X=4 is removed from the population, what is the value for the new mean? a. μ=9 b. μ=10 c. μ=8 d. μ=7
What is the population standard deviation using the following formula
Listed in the data table are IQ scores for a random sample of subjects with medium lead levels in their blood. Also listed are statistics from a study done of IQ scores for a random sample of subjects with high lead levels. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Click the icon to view the data table of IQ scores. a. Use a 0.05 significance level to test the claim that the mean IQ scores for subjects with medium lead levels is higher than the mean for subjects with high lead levels. What are the null and alternative hypotheses? Assume that population 1 consists of subjects with medium lead levels and population 2 consists of subjects with high lead levels. X A. Ho: H₁ H₂ H₁ H₁ H₂ c. Ho: M₁ = H₂ H₁: H₁ H₂ The test statistic is 0.56. (Round to two decimal places as needed.) The P-value is (Round to three decimal…
refer to image
Find the mean X̅ and the standard deviation S of the following data: i Xi 1 6 2 16 3 20 4 15 the mean X̅ = the standard deviation S =
Use the following set of values for #10 - 13. Round answers to nearest hundredth, if necessary. .3, .6, 9, 1.3, .4, .6, 1.2, 1.4, 1.1, .2, .2 10. Find the mean, median, and mode(s) 11. Find the range 12. Find the interquartile range 13. Find the standard deviation
Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 52.5 degrees. Low Temperature (o F) 40 - 44 45 - 49 50 - 54 55 - 59 60 – 64 D Frequency 2 9. ... The mean of the frequency distribution is degrees. (Round to the nearest tenth as needed.) Which of the following best describes the relationship between the computed mean and the actual mean? O A. The computed mean is close to the actual mean because the difference between the means is more than 5% of the actual mean. B. The computed mean is not close to the actual mean because the difference between the means is less than 5% of the actual mean. C. The computed mean is not close to the actual mean because the difference between the means is more than 5% of the actual mean. D. The computed mean is close to the actual mean because the difference between the means is less than 5% of the actual mean.

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