A data set includes data from student evaluations of courses. The summary statistics are n = 93, x= 3.69, s=0.59. Use a 0.10 significance level to test the claim that the population ofstudent course evaluations has a mean equal to 3.75. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, andstate the final conclusion that addresses the original claim.chWhat are the null and alternative hypotheses?OA. Ho: H=3.75H₁: µ>3.75OC. Ho: µ#3.75H₁: µ=3.75Determine the test statistic.(Round to two decimal places as needed.)Determine the P-value.(Round to three decimal places as needed.)State the final conclusion that addresses the original claim.Ho- There isTech help380 -aEDC$4888RFV%5TGBevidence to conclude that the mean of the population of student course evaluations is equal to 3.75MacBook AirYH&7NU***J* 00OB. Ho: μ=3.75H₁: μ<3.758OD. Ho: μ=3.75H₁:μ*3.75MI9KOJAGLcommandY correct.P.{alt[option?Next}delete

Given claim: The population of student course evaluations has a mean equal to 3.75. Null Hypothesis:…

Answered: A data set includes data from student…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Historically, the percentage of U.S. residents who support stricter gun control laws has been 55%. A recent Gallup Poll of 2500 people showed 1723 in favor of stricter gun control laws . Assume the poll was given to a random sample of people. QUESTION Test the claim that the proportion of those favoring stricter gun control has changed from 0.55. Perform a hypothesis test, using a significance level of 0.01. . What is the Z crit? +/- 1.96 +/- 1.645 +/- 2.58 +/- 2.326
The average retirement age in America is 66 years old. Do small business owners retire at an older average age? The data below shows the results of a survey of small business owners who have recently retired. Assume that the distribution of the population is normal. 63, 74, 59, 64, 74, 60, 71, 67, 65, 70, 63 What can be concluded at the the � = 0.05 level of significance level of significance? For this study, we should use The null and alternative hypotheses would be: �0: �1: The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is � Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton mean is significantly older than 66 at � = 0.05, so there is sufficient evidence to conclude that the population mean retirement age for small business owners is older than 66. The data suggest…
A data set includes data from 500 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.4 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. i Click the icon to view the display from technology. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? O A. Ho: μ=2.4 miles O B. Ho: μ=2.4 miles H₁: μ#2.4 miles H₁: μ 2.4 miles Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is greater than 2.4 miles evidence to support the claim that the mean tornado length is
The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? O A. Ho: H =5.00 Mbps O B. Ho: H5.00 Mbps H,: µ = 5.00 Mbps O C. Ho: H = 5.00 Mbps O D. Ho: H= 5.00 Mbps H: u#5.00 Mbps H1: µ<5.00 Mbps Identify the test statistic. (Round to two decimal places as needed.) Identify the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. Ho. There is evidence to support the claim that the sample is from a…
The display provided from technology available below results from using data for a smartphone carrier's data speeds at airports to test the claim that they are from a population having a mean less than 5.00 Mbps. Conduct the hypothesis test using these results. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. Click the icon to view the display from technology. Assuming all conditions for conducting a hypothesis test are met, what are the null and alternative hypotheses? O A. Ho: H5.00 Mbps
A data set includes data from 400 random tornadoes. The display from the technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.5 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the test statistic and P-value?
please solve
Give hypothesis, rejection region and test statistic and conclusion please.
The Woodcock-Johnson Cognitive Ability test indicates that the average score is 95. The same group of 12th grade students (n = 72) in Columbus are tested and the sample mean is 110.1 and the sample standard deviation is 15.2. Do the scores provide good evidence that the mean IQ of this population is greater than 95? What is the p-value for this data what is your decision about the null hypothesis? reject or fail to reject?
Salma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…
Please no written by hand solution and no img 4c. (Quantitative variable) Set up a T-distribution hypothesis test (StatCrunch T- stats -> One Sample). Copy and paste your results from StatCrunch into the write up. Explain the results (reject ?0 or fail to reject ?0) at the ?=0.05 significance level and at the ?=0.01 significance level. It is ok if this is the same question you used to construct the T-distribution confidence interval, if you don’t have enough quantitative questions in your survey to use a different question. Example hypothesis tests are in Chapter 7. Is the average mean of age for women higher than 0.05 and 0.01?
Identify the test statistic. Identify the P-value. State the final conclusion that addresses the original claim.

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