### Hypothesis Testing on Student Course EvaluationsA data set includes data from student evaluations of courses. The summary statistics are as follows:- Sample size ($n$) = 83- Sample mean ($\bar{x}$) = 3.65- Sample standard deviation ($s$) = 0.51Use a 0.10 significance level to test the claim that the population of student course evaluations has a mean equal to 3.75. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.#### What are the null and alternative hypotheses?- **Option A** - $H_0$: $\mu = 3.75$ - $H_1$: $\mu > 3.75$- **Option B** - $H_0$: $\mu = 3.75$ - $H_1$: $\mu < 3.75$- **Option C** - $H_0$: $\mu \neq 3.75$ - $H_1$: $\mu = 3.75$- **Option D (Selected)** - $H_0$: $\mu = 3.75$ - $H_1$: $\mu \neq 3.75$#### Determine the test statistic.- Round to two decimal places as needed.

Answered: Image /qna-images/answer/86f2b55b-d2fd-4820-af91-994146c2d671.jpg

Answered: A data set includes data from student…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A data set includes data from student evaluations of courses. The summary statistics are nequals=8585, x overbarxequals=3.423.42, sequals=0.540.54. Use a 0.010.01 significance level to test the claim that the population of student course evaluations has a mean equal to 3.503.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim.
Data were collected from 400 patients in the US about their estrogen level. Out of the 400, 35 patient have abnormal estrogen levels. On a national level, 8 % of patients have abnormal estrogen level. Researchers want to know the sample proportion differs from the national level. 5% is used for significance. Give the Ho and Ha. The appropriate test. Decision rule. Test calculations. Conclusion with comparison to alpha or critical value. I think this is a two tailed test. Use a one sample t- test. I think the null is rejected. t (40-1) = (400-35) / (.05 divided by sqrt 31) This is where I get stuck.
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identify the test statistic. Identify the P-value.
A data set includes data from student evaluations of courses. The summary statistics are n=97, x=3.44, s=0.61. Use a 0.05 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternativehypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. What are the null and alternative hypotheses? A. H0: μ=3.50 H1: μ≠3.50 B. H0: μ=3.50 H1: μ>3.50 C. H0: μ=3.50 H1: μ<3.50 D. H0: μ≠3.50 H1: μ=3.50 Determine the test statistic. nothing (Round to two decimal places as needed.) Determine the P-value. nothing (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. ▼ Fail to reject Reject H0. There is ▼ sufficient not sufficient evidence to conclude that the mean…
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please help me dtermine the test statistic AND P-value?
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