A dairy farmer chooses between two types of food for his small herd of cows. Let x be the number of pounds of alfalfa hay and y be the number of pounds of ground ears of corn to be bought. How many pounds of each food should be purchased in order to meet the nutritiona requirements at the least cost, if the objective function is x + 1.6y? (See the graph of the feasible set on the right.)
A dairy farmer chooses between two types of food for his small herd of cows. Let x be the number of pounds of alfalfa hay and y be the number of pounds of ground ears of corn to be bought. How many pounds of each food should be purchased in order to meet the nutritiona requirements at the least cost, if the objective function is x + 1.6y? (See the graph of the feasible set on the right.)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:A dairy farmer chooses between two
types of food for his small herd of cows.
Let x be the number of pounds of alfalfa
hay and y be the number of pounds of
ground ears of com to be bought. How
many pounds of each food should be
purchased in order to meet the nutritional
requirements at the least cost, if the
objective function is x + 1.6y? (See the
graph of the feasible set on the right.)
The number of pounds of affalfa hay, x,
is equal to
65,000
26,000
x=19,000
feasible
set
y=-2x+65,000
y=-0.5x+26,
32,500 52,000
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