A cylindrical mailing tube has a volume of 311 cubic inches and a diameter of 6 inches. Using T 3.14, what is the length of the cylinder rounded to the nearest whole number? A 3 B 10 11 D 33

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Chapter62: Volumes Of Prisms And Cylinders
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Using 3.14, what is the length of the cylinder rounded to the nearest whole number?
### Problem 7: Cylindrical Mailing Tube Problem

A cylindrical mailing tube has a volume of 311 cubic inches and a diameter of 6 inches.

Using \(\pi = 3.14\), what is the length of the cylinder rounded to the nearest whole number?

**Options:**

- A) 3
- B) 10
- C) 11
- D) 33

#### Explanation:

To solve for the length of the cylinder, we use the volume formula for a cylinder:

\[ V = \pi r^2 h \]

Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height (or length in this context),
- \(\pi \) is approximately equal to 3.14.

Given:
- \( V = 311 \) cubic inches,
- Diameter = 6 inches, hence the radius \( r = \frac{Diameter}{2} = \frac{6}{2} = 3 \) inches.

Substituting the known values into the formula:

\[ 311 = 3.14 \times 3^2 \times h \]
\[ 311 = 3.14 \times 9 \times h \]
\[ 311 = 28.26 \times h \]
\[ h \approx \frac{311}{28.26} \]
\[ h \approx 11 \]

Therefore, the length of the cylinder is approximately 11 inches.

**Answer: C) 11**
Transcribed Image Text:### Problem 7: Cylindrical Mailing Tube Problem A cylindrical mailing tube has a volume of 311 cubic inches and a diameter of 6 inches. Using \(\pi = 3.14\), what is the length of the cylinder rounded to the nearest whole number? **Options:** - A) 3 - B) 10 - C) 11 - D) 33 #### Explanation: To solve for the length of the cylinder, we use the volume formula for a cylinder: \[ V = \pi r^2 h \] Where: - \( V \) is the volume, - \( r \) is the radius, - \( h \) is the height (or length in this context), - \(\pi \) is approximately equal to 3.14. Given: - \( V = 311 \) cubic inches, - Diameter = 6 inches, hence the radius \( r = \frac{Diameter}{2} = \frac{6}{2} = 3 \) inches. Substituting the known values into the formula: \[ 311 = 3.14 \times 3^2 \times h \] \[ 311 = 3.14 \times 9 \times h \] \[ 311 = 28.26 \times h \] \[ h \approx \frac{311}{28.26} \] \[ h \approx 11 \] Therefore, the length of the cylinder is approximately 11 inches. **Answer: C) 11**
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