A cylindrical container with both ends closed has a radius r cm and a volume100 cm³. Determine the surface area A of a container in terms of r. (Surfacearea A = 2nr? + 2arh, Volume =%3DO A.A = 50r – -ar³2O B.200A= 2πrrA = 50r – ar3200O D. A = 2Ttr²-r

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Answered: A cylindrical container with both ends…

Calculus: Early Transcendentals

8th Edition

ISBN:9781285741550

Author:James Stewart

Publisher:James Stewart

Chapter1: Functions And Models

Section: Chapter Questions

Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...

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We'll be analyzing the surface area of a round cylinder - in other words the amount of material needed to "make a can". The height of the cylinder is 8 inches. A cylinder (round can) has a circular base and a circular top with vertical sides in between. Let r be the radius of the top of the can and let h be the height. The surface area of the cylinder, A , is A=2πr2+2πrh (it's two circles for the top and bottom plus a rolled up rectangle for the side). Part A: Assume that the height of your cylinder is 8 inches. Consider A as a function of r, so we can write that as A(r)=2πr^2+16 πr. What is the domain of A(r)? In other words, for which values of r is A(r) defined? I believe the answer to this part is "All real numbers" Part B: Continue to assume that the height of your cylinder is 8 inches. Write the radius r as a function of A. This is the inverse function to A(r), i.e to turn A as a function of r into. r as a function of A. For this part nothing I have written is working. Any help…

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A cylindrical container with both ends closed has a radius r cm and a volume 100 cm³. Determine the surface area A of a container in terms of r. (Surface area A = 2nr? + 2arh, Volume = %3D O A. A = 50r – -ar³ 2 O B. 200 A= 2πr r A = 50r – ar3 200 O D. A = 2Ttr² - r