A cylinder (round can) has a circular base and a circular top with vertical sides in between. Let r be the radius of the top of the can and let h be the height. The surface area of the cylinder, A, is A = 2Tr2 + 2rrh (it's two circles for the top and bottom plus a rolled up rectangle for the side).
A cylinder (round can) has a circular base and a circular top with vertical sides in between. Let r be the radius of the top of the can and let h be the height. The surface area of the cylinder, A, is A = 2Tr2 + 2rrh (it's two circles for the top and bottom plus a rolled up rectangle for the side).
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Assume that the height of your cylinder is 6 inches. Consider A as a function of r, so we can write that as A(r)=2πr2+12πr. What is the domain of A(r)? In other words, for which values of r is A(r) defined?
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radius of the top of the can and let h be the height. The surface area of the cylinder, A, is
A = 2Tr2 + 2rrh (it's two circles for the top and bottom plus a rolled up rectangle for the side).
r = radius
Areas = r²
h = height
Area = h(2rr)
Circumference
2ar"
Transcribed Image Text:A cylinder (round can) has a circular base and a circular top with vertical sides in between. Let r be the
radius of the top of the can and let h be the height. The surface area of the cylinder, A, is
A = 2Tr2 + 2rrh (it's two circles for the top and bottom plus a rolled up rectangle for the side).
r = radius
Areas = r²
h = height
Area = h(2rr)
Circumference
2ar
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