A cylinder of weight 20 lb slides in a lubricated pipe. as shown in Fig. I-7. The clearance between cylinder and pipe is 0.001 in. If the cylinder is observed to decelerate at a rate of 2 ft/s when the speed is 20 ft!s. what is the viscosity. of the oil? T= u (du/dy) = (u/(0.001/12)]=12 000µuv Fy=TA = 12 000uv(7)(Á)() = 7854 20 - (7854)(4)(20) = (20/32.2)(-2) %3D u = 1.35 x 10 1b s/ft 2F =ma %3D 6 in-
A cylinder of weight 20 lb slides in a lubricated pipe. as shown in Fig. I-7. The clearance between cylinder and pipe is 0.001 in. If the cylinder is observed to decelerate at a rate of 2 ft/s when the speed is 20 ft!s. what is the viscosity. of the oil? T= u (du/dy) = (u/(0.001/12)]=12 000µuv Fy=TA = 12 000uv(7)(Á)() = 7854 20 - (7854)(4)(20) = (20/32.2)(-2) %3D u = 1.35 x 10 1b s/ft 2F =ma %3D 6 in-
Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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![A cylinder of weight 20 lb slides in a lubricated pipe. as shown in Fig. 1-7. The clearance between cylinder and
pipe is 0.001 in. If the cylinder is observed to decelerate at a rate of 2 ft/s' when the speed is 20 ft!s, what is the
viscosity. of the oil?
T=u (du/dy) = {v/(0.001/12)]=12 000uv
F,= TA = 12000uv((7)(6))) = 7854
2F = ma
20 - (7854)(4)(20) = (20/32.2)(-2)
u= 1.35 x 10 1b s/ft
5 in
-6 in-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffd921ff2-93fc-4b0c-8ba2-d77048721f69%2Fc7dc3c83-e9af-4390-9b76-6165e1ddc5bc%2F91voxno_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A cylinder of weight 20 lb slides in a lubricated pipe. as shown in Fig. 1-7. The clearance between cylinder and
pipe is 0.001 in. If the cylinder is observed to decelerate at a rate of 2 ft/s' when the speed is 20 ft!s, what is the
viscosity. of the oil?
T=u (du/dy) = {v/(0.001/12)]=12 000uv
F,= TA = 12000uv((7)(6))) = 7854
2F = ma
20 - (7854)(4)(20) = (20/32.2)(-2)
u= 1.35 x 10 1b s/ft
5 in
-6 in-
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