A cylinder contains 19.16 mol of carbon dioxide and has a volume of 4.94 L. The gas is at a temperature of 300.56 K. Using the Van de Waals equation, what is the pressure inside the cylinder in atmospheres? -Remember, 1 bar = 0.9869 atm. Report your answer using three significant figures. Table 1. Van der Waals constants for carbon dioxide. carbon dioxide a L-bar mol² 3.640 L-bar mol-K R=0.08314- b(l) mol 0.04267
A cylinder contains 19.16 mol of carbon dioxide and has a volume of 4.94 L. The gas is at a temperature of 300.56 K. Using the Van de Waals equation, what is the pressure inside the cylinder in atmospheres? -Remember, 1 bar = 0.9869 atm. Report your answer using three significant figures. Table 1. Van der Waals constants for carbon dioxide. carbon dioxide a L-bar mol² 3.640 L-bar mol-K R=0.08314- b(l) mol 0.04267
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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![A cylinder contains 19.16 mol of carbon dioxide and has a volume of 4.94 L. The gas is at a
temperature of 300.56 K. Using the Van de Waals equation, what is the pressure inside the cylinder
in atmospheres? -Remember, 1 bar = 0.9869 atm. Report your answer using three significant figures.
Table 1. Van der Waals constants for carbon dioxide.
carbon
dioxide
a
L-bar
mol²
3.640
L-bar
mol-K
R = 0.08314-
b(l)
0.04267](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd9611388-bc49-4c5e-a899-f63b8b6c2b2c%2Ff3c157b7-9c06-436f-8480-5c0a30876e09%2Fo6yodq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A cylinder contains 19.16 mol of carbon dioxide and has a volume of 4.94 L. The gas is at a
temperature of 300.56 K. Using the Van de Waals equation, what is the pressure inside the cylinder
in atmospheres? -Remember, 1 bar = 0.9869 atm. Report your answer using three significant figures.
Table 1. Van der Waals constants for carbon dioxide.
carbon
dioxide
a
L-bar
mol²
3.640
L-bar
mol-K
R = 0.08314-
b(l)
0.04267
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