A cyanide solution with a volume of 12.02 mL12.02 mL was treated with 20.00 mL20.00 mL of Ni2+Ni2+ solution (containing excess Ni2+Ni2+) to convert the cyanide into tetracyanonickelate(II): 4CN−+Ni2+⟶Ni(CN)2−44CN−+Ni2+⟶Ni(CN)42− The excess Ni2+Ni2+ was then titrated with 11.49 mL11.49 mL of 0.01257 M0.01257 M ethylenediaminetetraacetic acid (EDTA): Ni2++EDTA4−⟶Ni(EDTA)2−Ni2++EDTA4−⟶Ni(EDTA)2− Ni(CN)2−4Ni(CN)42− does not react with EDTA. If 39.02 mL39.02 mL of EDTA were required to react with 30.34 mL30.34 mL of the original Ni2+Ni2+ solution, calculate the molarity of CN−CN− in the 12.02 mL12.02 mL cyanide sample. [CN−]= M
A cyanide solution with a volume of 12.02 mL12.02 mL was treated with 20.00 mL20.00 mL of Ni2+Ni2+ solution (containing excess Ni2+Ni2+) to convert the cyanide into tetracyanonickelate(II): 4CN−+Ni2+⟶Ni(CN)2−44CN−+Ni2+⟶Ni(CN)42− The excess Ni2+Ni2+ was then titrated with 11.49 mL11.49 mL of 0.01257 M0.01257 M ethylenediaminetetraacetic acid (EDTA): Ni2++EDTA4−⟶Ni(EDTA)2−Ni2++EDTA4−⟶Ni(EDTA)2− Ni(CN)2−4Ni(CN)42− does not react with EDTA. If 39.02 mL39.02 mL of EDTA were required to react with 30.34 mL30.34 mL of the original Ni2+Ni2+ solution, calculate the molarity of CN−CN− in the 12.02 mL12.02 mL cyanide sample. [CN−]= M
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A cyanide solution with a volume of 12.02 mL12.02 mL was treated with 20.00 mL20.00 mL of Ni2+Ni2+ solution (containing excess Ni2+Ni2+) to convert the cyanide into tetracyanonickelate(II):
4CN−+Ni2+⟶Ni(CN)2−44CN−+Ni2+⟶Ni(CN)42−
The excess Ni2+Ni2+ was then titrated with 11.49 mL11.49 mL of 0.01257 M0.01257 M ethylenediaminetetraacetic acid (EDTA):
Ni2++EDTA4−⟶Ni(EDTA)2−Ni2++EDTA4−⟶Ni(EDTA)2−
Ni(CN)2−4Ni(CN)42− does not react with EDTA. If 39.02 mL39.02 mL of EDTA were required to react with 30.34 mL30.34 mL of the original Ni2+Ni2+ solution, calculate the molarity of CN−CN− in the 12.02 mL12.02 mL cyanide sample.
[CN−]= M
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