A current I = 30 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.18 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes.
A current I = 30 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.18 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A current I = 30 A is directed along the positive x-axis and perpendicular to a magnetic field. A magnetic force per unit length of 0.18 N/m acts on the conductor in the negative y-direction. Calculate the magnitude and direction of the magnetic field in the region through which the current passes.
magnitude | _____T |
direction |
A. +x direction B. -x direction C. +y direction D. -y direction E. +z direction F. -z direction |
Expert Solution
Step 1
The current (along x axis)
Magnetic force per unit length (in -y direction)
The magnetic force can be calculated be the formula given below
Step 2
Using right hand rule to find the direction of cross product we get the magnetic field is in the -z direction.
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