A cube of mass m = 620 kg is totally immersed in a liquid of density ρ = 0.96 g/cm3. The cube has an edge length of L = 1.4 m and is held at a depth of d = 1.6 m from the top of the cube to the surface of the liquid. a. Enter an expression for the difference between the magnitude of the force the liquid exerts on the bottom surface of the cube and the magnitude of the force it exerts on the top surface, in terms of the defined quantities and the acceleration due to gravity, g. This is the magnitude of the net vertical force the liquid exerts on the cube. That force points up and is called the buoyant force, denoted Fb. b. Calculate the magnitude of the buoyant force, in newtons, that the li
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Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem to bother anyone as the bodily fluids are constantly pushing outwards with the same force but if one swims down into the ocean a few feet below the surface one can notice the difference, there is increased pressure on the eardrum, this is due to an increase in hydrostatic pressure.
A cube of mass m = 620 kg is totally immersed in a liquid of density ρ = 0.96 g/cm3. The cube has an edge length of L = 1.4 m and is held at a depth of d = 1.6 m from the top of the cube to the surface of the liquid.
a. Enter an expression for the difference between the magnitude of the force the liquid exerts on the bottom surface of the cube and the magnitude of the force it exerts on the top surface, in terms of the defined quantities and the acceleration due to gravity, g. This is the magnitude of the net vertical force the liquid exerts on the cube. That force points up and is called the buoyant force, denoted Fb.
b. Calculate the magnitude of the buoyant force, in newtons, that the liquid exerts on the cube.
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