A cube, 0.8 cm on a side, and a mass of 100 g is completely submerged under water (pwater = 1.0 g/cm3= 1000 kg/m3 ) and released. a) What is the density of the cube in g/cm3? b) Draw a free-body diagram for the cube. c) What is the buoyancy force on the cube? d) What is the acceleration of the block after being released under water? (include direction of acceleration in your answer)

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A cube, 0.8 cm on a side, and a mass of 100 g is completely submerged under water (pwater = 1.0 g/cm3=
1000 kg/m3 ) and released.
a) What is the density of the cube in g/cm3?
b) Draw a free-body diagram for the cube.
c) What is the buoyancy force on the cube?
d) What is the acceleration of the block after being released under water? (include direction of acceleration in
your answer)
Transcribed Image Text:A cube, 0.8 cm on a side, and a mass of 100 g is completely submerged under water (pwater = 1.0 g/cm3= 1000 kg/m3 ) and released. a) What is the density of the cube in g/cm3? b) Draw a free-body diagram for the cube. c) What is the buoyancy force on the cube? d) What is the acceleration of the block after being released under water? (include direction of acceleration in your answer)
Expert Solution
Step 1

Given data

*The mass of the cube is m = 100 g = 0.100 kg

*The side of the cube is a = 0.8 cm = 0.8 × 10-2 m

*The given density of water is ρwater=1.0 g/cm3 = 1000 kg/m3

Step 2

(a)

The expression for the density of the cube is given as,

D=mV=ma3

*Here V = a3 is the volume of the cube

Substitute the values in the above expression as

D=100 g0.8 cm3=195.31 g/cm3

Thus the density of the cube is D = 195.31 g/cm3

Step 3

(b)

The free-body diagram of the cube is given below

Physics homework question answer, step 3, image 1

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