A crate with mass m = 24 kg is being pushed up an incline that makes an angle φ = 18.7 degrees with horizontal. The pushing force is horizontal, with magnitude P = 460 N. Starting from rest, the crate achieves a speed of 4.8 m/s as it moves a distance d = 4.98 m. What is the work done by friction, in joules?

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A: W=work done by pushing force=friction work done +increase in KE

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A: Work done by the force is given as  W = F.r r = displacement vector

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A: Work done by gravitational force=mgh Here h is height of inclined

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A: Given that-Mass of the sled, m= 70 kgLength of the plane, L= 80 mAngle of inclination of the plane…

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A: Recall W=FdcosθHere angle θ between normal force and displacement is 900 so cos90=0

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