C. In page 6 of this lesson, we gave an example that included a list of the eight outcomes that are possible when a couple has three children. Refer to that list, and find the probability of each event. _11. Among three children, there is exactly one girl. _12. Among three children, there are exactly two girls.
C. In page 6 of this lesson, we gave an example that included a list of the eight outcomes that are possible when a couple has three children. Refer to that list, and find the probability of each event. _11. Among three children, there is exactly one girl. _12. Among three children, there are exactly two girls.
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Please answer this, Thank You!
Note: Page 6 was mentioned in the Activity C, you can find that in the second picture.
![C. In page 6 of this lesson, we gave an example that included a list of the
eight outcomes that are possible when a couple has three children.
Refer to that list, and find the probability of each event.
_11. Among three children, there is exactly one girl.
_12. Among three children, there are exactly two girls.
D. Page 6 of this lesson included a table summarizing the gender outcomes
for a couple planning to have three children.
_13. Construct a similar table for a couple planning to have two
children.
14. Assuming that the outcomes listed are equally likely, find the
probability of getting two girls.
_15. Find the probability of getting exactly one child of each gender.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F62119949-4dad-4ef2-9c02-583a818fd5da%2F2b75201c-ad6b-4ee4-b721-53733429a4c3%2Fnlx9r55_processed.jpeg&w=3840&q=75)
Transcribed Image Text:C. In page 6 of this lesson, we gave an example that included a list of the
eight outcomes that are possible when a couple has three children.
Refer to that list, and find the probability of each event.
_11. Among three children, there is exactly one girl.
_12. Among three children, there are exactly two girls.
D. Page 6 of this lesson included a table summarizing the gender outcomes
for a couple planning to have three children.
_13. Construct a similar table for a couple planning to have two
children.
14. Assuming that the outcomes listed are equally likely, find the
probability of getting two girls.
_15. Find the probability of getting exactly one child of each gender.
![EXAMPLE:
On an ACT or SAT test, a typical question has 5 possible answers. If an
examinee makes random guess on one such question, what is the probability
that the response is wrong?
SOLUTION:
There are 5 possible outcomes or answers, and there are 4 ways to answer
incorrectly. Random guessing implies that the outcomes are equally likely,
so we apply the classical approach to get
4
P(wrong answer) = =
= 0.8
EXAMPLE:
Find the probability that when a couple has 3 children, they will have
exactly 2 boys. Assume that boys and girls are equally likely and that the
gender of any child is not influenced by the gender of any other child.
SOLUTION:
The biggest obstacle here is correctly identifying the sample space. It
involves more than working only with the numbers 2 and 3 that were given
in the statement of the problem. The sample space consists of 8 different
ways that 3 children can occur, and we list them in the margin. Those 8
outcomes are equally likely, so we use Rule 2. Of those 8 different possible
outcomes, 3 correspond to exactly 2 boys, so
1st 2nd 3rd
boy-boy-boy
boy-boy-girl
eхаctly
+ boy-girl-boy
2 boys
boy-girl-girl
girl-boy-boy
girl-boy-girl
girl-girl-boy
girl-girl-girl
P(2 boys in 3 births) =
3
= 0.375
INTERPRETATION: There is a 0.375 probability that if a couple has 3
children, exactly 2 will be boys.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F62119949-4dad-4ef2-9c02-583a818fd5da%2F2b75201c-ad6b-4ee4-b721-53733429a4c3%2Fgidbbd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:EXAMPLE:
On an ACT or SAT test, a typical question has 5 possible answers. If an
examinee makes random guess on one such question, what is the probability
that the response is wrong?
SOLUTION:
There are 5 possible outcomes or answers, and there are 4 ways to answer
incorrectly. Random guessing implies that the outcomes are equally likely,
so we apply the classical approach to get
4
P(wrong answer) = =
= 0.8
EXAMPLE:
Find the probability that when a couple has 3 children, they will have
exactly 2 boys. Assume that boys and girls are equally likely and that the
gender of any child is not influenced by the gender of any other child.
SOLUTION:
The biggest obstacle here is correctly identifying the sample space. It
involves more than working only with the numbers 2 and 3 that were given
in the statement of the problem. The sample space consists of 8 different
ways that 3 children can occur, and we list them in the margin. Those 8
outcomes are equally likely, so we use Rule 2. Of those 8 different possible
outcomes, 3 correspond to exactly 2 boys, so
1st 2nd 3rd
boy-boy-boy
boy-boy-girl
eхаctly
+ boy-girl-boy
2 boys
boy-girl-girl
girl-boy-boy
girl-boy-girl
girl-girl-boy
girl-girl-girl
P(2 boys in 3 births) =
3
= 0.375
INTERPRETATION: There is a 0.375 probability that if a couple has 3
children, exactly 2 will be boys.
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