A copper(I) ion can act as both an oxidizing agent and a reducing agent. Hence, it can react with itself. 2Cu* (ag) → Cu(s) + Cu?+ (aq) Calculate the equilibrium constant at 25°C for this reaction. You may need to use the following data: Cathode (Reduction) Standard Half-Reaction Potential, E (V) Cu?+ (ag) +e Cu* (ag) 0.16 Cu* (aq) +e Cu(s) 0.52 (Enter your answer to two significant figures.)

Chemistry: The Molecular Science
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Chapter17: Electrochemistry And Its Applications
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A copper(I) ion can act as both an oxidizing agent and a reducing agent. Hence, it can react with itself.
2Cu* (ag) → Cu(s) + Cu?+ (aq)
Calculate the equilibrium constant at 25°C for this reaction. You may need to use the following data:
Cathode (Reduction)
Standard
Half-Reaction
Potential, E (V)
Cu?+ (ag) +e Cu* (ag)
0.16
Cu* (aq) +e Cu(s)
0.52
(Enter your answer to two significant figures.)
Transcribed Image Text:A copper(I) ion can act as both an oxidizing agent and a reducing agent. Hence, it can react with itself. 2Cu* (ag) → Cu(s) + Cu?+ (aq) Calculate the equilibrium constant at 25°C for this reaction. You may need to use the following data: Cathode (Reduction) Standard Half-Reaction Potential, E (V) Cu?+ (ag) +e Cu* (ag) 0.16 Cu* (aq) +e Cu(s) 0.52 (Enter your answer to two significant figures.)
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