A conveyer belt at the postal service deposits packages down a chute of radius p to be sorted. At the instant shown, package B is resting at the end of the chute while package A has just entered the chute at a height h with velocity VA. After going down the chute package A and B become stuck together. Part A: What is the velocity of the packages after they impact? Part B: Using the angular momentum form of Newton's 2nd Law determine how fast the velocity is increasing, v, at the instant when 0 = 70 deg. (Hint: To compute the angular momentum, use a polar frame with VA/O= vêe.) Values: g= 9.81 m/s², mA = 5 kg, mB = 8 kg, VA = 5 m/s, h = p = 1.5 m CONVEYER TIC h SMOOTH CHUTE VA 9 1 at rest •B
A conveyer belt at the postal service deposits packages down a chute of radius p to be sorted. At the instant shown, package B is resting at the end of the chute while package A has just entered the chute at a height h with velocity VA. After going down the chute package A and B become stuck together. Part A: What is the velocity of the packages after they impact? Part B: Using the angular momentum form of Newton's 2nd Law determine how fast the velocity is increasing, v, at the instant when 0 = 70 deg. (Hint: To compute the angular momentum, use a polar frame with VA/O= vêe.) Values: g= 9.81 m/s², mA = 5 kg, mB = 8 kg, VA = 5 m/s, h = p = 1.5 m CONVEYER TIC h SMOOTH CHUTE VA 9 1 at rest •B
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:**Problem**
A conveyor belt at the postal service deposits packages down a chute of radius \( \rho \) to be sorted. At the instant shown, package \( B \) is resting at the end of the chute while package \( A \) has just entered the chute at a height \( h \) with velocity \( v_A \). After going down the chute package \( A \) and \( B \) become stuck together.
**Part A:** What is the velocity of the packages after they impact?
**Part B:** Using the angular momentum form of Newton’s 2nd Law, determine how fast the velocity is increasing, \( \dot{v} \), at the instant when \( \theta = 70 \) degrees. (Hint: To compute the angular momentum, use a polar frame with \( \mathbf{v}_{A/O} = v \mathbf{e}_\theta \).)
**Values:**
\( g = 9.81 \, \text{m/s}^2, \, m_A = 5 \, \text{kg}, \, m_B = 8 \, \text{kg}, \, v_A = 5 \, \text{m/s}, \, h = \rho = 1.5 \, \text{m} \)
**Diagram Explanation:**
The diagram illustrates a smooth chute under a conveyor belt. Package \( A \) is depicted at the top of the chute entering with velocity \( v_A \), while package \( B \) is shown at rest at the end of the chute. An arrow indicates the velocity vector of package \( A \). The chute is curved with a radius \( \rho \), and angle \( \theta \) is marked at the point where package \( A \) is located. These elements are used to visualize the problem and the physical interactions as the packages move and eventually collide.
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