**Question:** A container of 5 L water is left out on a hot day. A temperature change of 2.5°C was noted. Estimate the heat transfer that took place. (Ignore all other heat loss)**Explanation for Educational Use:** This problem involves calculating the heat transfer that occurs when a known volume of water undergoes a temperature change. To estimate the heat transfer, we can use the formula \( Q = mc\Delta T \), where:- \( Q \) is the heat transfer (in joules),- \( m \) is the mass of the water (in kilograms),- \( c \) is the specific heat capacity of water (approximately \( 4,186 \, \text{J/kg}^\circ\text{C} \)),- \( \Delta T \) is the change in temperature (in degrees Celsius).Given:- Volume of water = 5 L (which is equivalent to 5 kg, assuming the density of water is \( 1 \, \text{kg/L} \)),- Temperature change (\( \Delta T \)) = 2.5°C.Substitute these values into the equation to find the heat transfer.

Whenever a system undergoes temperature change there will be a change in heat energy. This change in…

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