A consulting agency was asked by a large insurance company to investigate if business majors were better salespersons than those with other majors. A sample of 20 salespersons with a business degree showed that they sold an average of 11 insurance policies week. Another sample of 25 salespersons with a degree other than business showed that they sold an average of 9 insurance policies per week. Assume that the two populations are approximately normally distributed with population standard deviations of 1.80 a policies per week, respectively. Calculate the 95% confidence interval for the difference between the mean stress scores of all executives and all professors. (round your values to two decimal places) =(

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A consulting agency was asked by a large insurance company to investigate if business majors were better salespersons than those with other majors. A sample of 20 salespersons with a business degree showed that they sold an average of 11 insurance policies per
week. Another sample of 25 salespersons with a degree other than business showed that they sold an average of 9 insurance policies per week. Assume that the two populations are approximately normally distributed with population standard deviations of 1.80 and 1.35
policies per week, respectively. Calculate the 95% confidence interval for the difference between the mean stress scores of all executives and all professors. (round your values to two decimal places) = (
Transcribed Image Text:A consulting agency was asked by a large insurance company to investigate if business majors were better salespersons than those with other majors. A sample of 20 salespersons with a business degree showed that they sold an average of 11 insurance policies per week. Another sample of 25 salespersons with a degree other than business showed that they sold an average of 9 insurance policies per week. Assume that the two populations are approximately normally distributed with population standard deviations of 1.80 and 1.35 policies per week, respectively. Calculate the 95% confidence interval for the difference between the mean stress scores of all executives and all professors. (round your values to two decimal places) = (
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