A= Consider the following compounds D-HOCH CH B. E = C = F= a) Which one(s) would give a positive Tollens (silver mirror) test? A. I b) Which one(s) could be oxidized with Cro? D Which one(s) could be reduced with NaBH? E A d) Which one(s) would dissolve in water? D e) Which one(s) would have a peak in the 'H NMR spectrum which would B disappear when DiO is added?

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**Title: Analyzing Organic Compounds Using Various Tests**

**Introduction:**
This educational module focuses on analyzing specific organic compounds through chemical tests and reactions, such as Tollens' test, oxidation, reduction, solubility, and NMR spectroscopy. 

**Compounds:**
- **A:** \( \text{(CH}_3\text{O)}_2\text{C=O} \) 
- **B:** \( \text{Benzaldehyde (C}_6\text{H}_5\text{CHO)} \)
- **C:** \( \text{Cyclohexanone (C}_6\text{H}_{10}\text{O)} \)
- **D:** \( \text{Ethanol (HOCH}_2\text{CH}_3) \)
- **E:** \( \text{Styrene (C}_8\text{H}_8) \)
- **F:** \( \text{Phenethyl alcohol (C}_8\text{H}_{10}\text{O)} \)

**Questions and Answers:**

a) **Which one(s) would give a positive Tollens' (silver mirror) test?**
   - **Answer:** A

b) **Which one(s) could be oxidized with CrO3?**
   - **Answer:** D

c) **Which one(s) could be reduced with NaBH4?**
   - **Answer:** A, C

d) **Which one(s) would dissolve in water?**
   - **Answer:** D

e) **Which one(s) would have a peak in the 'H NMR spectrum which would disappear when D2O is added?**
   - **Answer:** B

**Discussion:**
1. **Tollens' Test:**
   - A Tollens' test is used to identify aldehydes. Compound A contains an acetal group that can potentially react under these conditions.

2. **Oxidation with CrO3:**
   - Ethanol (D) can be oxidized to an aldehyde or carboxylic acid.

3. **Reduction with NaBH4:**
   - Both ketones (C) and certain esters/aldehydes (A) can be reduced by sodium borohydride.

4. **Solubility in Water:**
   - Ethanol (D) is soluble in water due
Transcribed Image Text:**Title: Analyzing Organic Compounds Using Various Tests** **Introduction:** This educational module focuses on analyzing specific organic compounds through chemical tests and reactions, such as Tollens' test, oxidation, reduction, solubility, and NMR spectroscopy. **Compounds:** - **A:** \( \text{(CH}_3\text{O)}_2\text{C=O} \) - **B:** \( \text{Benzaldehyde (C}_6\text{H}_5\text{CHO)} \) - **C:** \( \text{Cyclohexanone (C}_6\text{H}_{10}\text{O)} \) - **D:** \( \text{Ethanol (HOCH}_2\text{CH}_3) \) - **E:** \( \text{Styrene (C}_8\text{H}_8) \) - **F:** \( \text{Phenethyl alcohol (C}_8\text{H}_{10}\text{O)} \) **Questions and Answers:** a) **Which one(s) would give a positive Tollens' (silver mirror) test?** - **Answer:** A b) **Which one(s) could be oxidized with CrO3?** - **Answer:** D c) **Which one(s) could be reduced with NaBH4?** - **Answer:** A, C d) **Which one(s) would dissolve in water?** - **Answer:** D e) **Which one(s) would have a peak in the 'H NMR spectrum which would disappear when D2O is added?** - **Answer:** B **Discussion:** 1. **Tollens' Test:** - A Tollens' test is used to identify aldehydes. Compound A contains an acetal group that can potentially react under these conditions. 2. **Oxidation with CrO3:** - Ethanol (D) can be oxidized to an aldehyde or carboxylic acid. 3. **Reduction with NaBH4:** - Both ketones (C) and certain esters/aldehydes (A) can be reduced by sodium borohydride. 4. **Solubility in Water:** - Ethanol (D) is soluble in water due
Expert Solution
Step 1

a) Tollen's test is given by compounds which have aldehyde groups. Out here, the compound A has a aldehydic CHO group. 

b) Oxidation with CrO3 converts alcohol to aldehyde/ketone. C and D are alcohol. But C cannot be oxidised as it has no Hydrogen. So, only D can be oxidised.

c) C=O can be reduced with NaBH4, only aldehyde and ketone, not ester group. So, B cannot be reduced but A and E can be. 

d) Alcohols readily dissolve in water as they can form hydrogen bonding. So, C and D

e) On adding D2O, tautomerism can occur and the Hydrogen at the alpha position can be exchanged with deuterium. So, a 1HNMR peak will disappear. Option E is correct.

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