**Problem Description:**A conical tank (point down) with height 10 ft and radius 5 ft is half-filled with oil. The density of the oil is 57 lb./ft³. Determine how much work is done to pump the oil to a point 4 feet above the top of the tank.**Diagram Explanation:**The diagram illustrates a conical tank oriented with the point down. The dimensions of the cone are labeled: the height is 10 ft and the top radius is 5 ft. The diagram indicates that the tank is half-filled with oil. An arrow pointing downward represents the density of the oil, which is given as ρ = 57 lb./ft³.A question is posed: "How much work to pump oil 4 ft above the tank?" This implies calculating the work needed to move the oil a total of 4 additional feet above the original top of the tank.

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Answered: A conical tank (point down) with height…

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A conical tank (point down) with height 10 ft and radius 5 ft is half-filled with oil (density of oil is 57 lb./ft3). How much work is done to pump oil to a point 4 feet above the top of the tank? loftn Sft How much work to pump oil. 4 ft above the tank?. P=57.161f73.