(a) Conductors of a 3-phase,60 Hz transmission line are arranged at the corners of a triangle of sides 20, 5, and 8 meters. The diameter of each line conductor is 1 cm. Calculate the capacitance (C1) per phase per km and capacitive reactance (Xc1)of the line. If the length of the transmission line is 64 km, determine the capacitance per phase(C2)and Capacitive reactance(Xc2). Assume En=8.854 x10-12 (b) Draw the positive, negative and zero sequence diagram of the system shown in Figure given below. Xg = j0.16 X2 = j0.17 Xo = j0.06 Line X1 =x2 = j0.10 Xo = j0.06 x4 = j0.2 13= 10.22 AY Xo = J0.15 X =X2 = X0jo.11 X -X2 - X - j0.11 Question(a) answer Capacitance (C1) in per phase per Km Capacitive reactance (Xc1) Capacitance per phase(C2)

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(a) Conductors of a 3-phase,60 Hz transmission line are arranged at the corners of a triangle of sides 20, 5, and 8 meters. The diameter of each line conductor
is 1 cm. Calculate the capacitance (C1) per phase per km and capacitive reactance (Xc1)of the line. If the length of the transmission line is 64 km, determine the
capacitance per phase(C2)and Capacitive reactance(Xc2). Assume En=8.854 x10-12
(b) Draw the positive, negative and zero sequence diagram of the system shown in Figure given below.
Xg = j0.16
Line
X2 = 0.17
X1 =x2 = j0.10
Xo = j0.06
Xo = j0.06
xa = j0.2
13= 10.22 AY
Xo = J0.15
X = X2 - X0 - j0.11
X -X2 - X - j0.11
Question(a) answer
Capacitance (C1) in per phase per Km
Capacitive reactance (Xc1)
Capacitance per phase(C2)
Capacitive reactance (Xc2)
ele
Transcribed Image Text:(a) Conductors of a 3-phase,60 Hz transmission line are arranged at the corners of a triangle of sides 20, 5, and 8 meters. The diameter of each line conductor is 1 cm. Calculate the capacitance (C1) per phase per km and capacitive reactance (Xc1)of the line. If the length of the transmission line is 64 km, determine the capacitance per phase(C2)and Capacitive reactance(Xc2). Assume En=8.854 x10-12 (b) Draw the positive, negative and zero sequence diagram of the system shown in Figure given below. Xg = j0.16 Line X2 = 0.17 X1 =x2 = j0.10 Xo = j0.06 Xo = j0.06 xa = j0.2 13= 10.22 AY Xo = J0.15 X = X2 - X0 - j0.11 X -X2 - X - j0.11 Question(a) answer Capacitance (C1) in per phase per Km Capacitive reactance (Xc1) Capacitance per phase(C2) Capacitive reactance (Xc2) ele
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