A concentration cell is constructed using two Pb/Pb4+ half-cells. If the [Pb4+] in one of the half-cells is 6.74 M, what would it have to be in the other half cell for the concentration cell to produce exactly 0.0192 V? Assume the cell operates at 25°C. Answer: M

A concentration cell is constructed using two Pb/Pb4+ half-cells. If the [Pb4+] in one of the half-cells is 6.74 M, what would it have to be in the other half cell for the concentration cell to produce exactly 0.0192 V? Assume the cell operates at 25°C. Answer: M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Related questions

Q: When the Hg2+ concentration is 1.35 M, the observed cell potential at 298K for an electrochemical…

Q: When the Hg2+ concentration is 1.01 M, the observed cell potential at 298K for an electrochemical…

A: The concentration of Hg2+ is 1.01 M, the observed cell potential( E cell)at 298K for an…

Q: A galvanic cell at a temperature of 25.0 °C is powered by the following redox reaction: 3Cu?* (aq)…

A: Since in the above reaction, Cu2+ is being reduced to Cu and Al is being oxidised to Al3+ Hence the…

Q: A voltaic cell is based on the reaction 2+ Sn(s) + I₂(s)→Sn²+ (aq) + 2I¯(aq). Part A Under standard…

A: The Overall reaction is,

Q: electrochemical

A: Part-A : E°cell = E°( cathode ) - E°( anode ) E°cell = 1.09 - ( -0.76 ) E°cell = 1.09 + 0.76…

Q: a)What is K for the spontaneous reaction 3 Zn2+ + 2 Al (s) ↔ 2 Al3+ + 3 Zn(s) ? b)What potential…

A: The equilibrium constant of the given reaction represents the ratio of the concentration of products…

Q: When the Pb2+ concentration is 1.18 M, the observed cell potential at 298K for an electrochemical…

A: We would use nernest equation at 298 K to calculate Concentration of Mg2+. For this we would first…

Q: When [Hg2+] = 1.16 M, the observed cell potential at 298 K for an electrochemical cell with the…

Q: A voltaic cell is constructed that is based on the following reaction: Sn2+1aq2 + Pb1s2 ¡ Sn1s2 +…

A: GIVEN: Cell reaction: emf of the cell= 0.22 V concentration of Sn2+ in the cathode half-cell = 1.00…

Q: Au3+ +3e- ↔ Au E0 = + 1,42 V Pb2+ + 2e- ↔ Pb E0 = - 0,26 V When the cell works voluntarily,…

A: Half cell which have more reduction potential value undergo at cathode and which have less reduction…

Q: Consider a voltaic cell at 25°C consisting of a Co(s) electrode immersed in a 1.0 M Co(NO3)2…

A: Given : [Co(NO3)2] = 1.0 M [Al(NO3)3] = 1.0 M

Q: Salt bridge A concentration cell similar to the one shown is composed of two Pb electrodes and…

Q: a silver/aluminum cell (e°cell 2.462 V) constructed from one half cell with an aluminum electrode…

A: Given,standard cell potential ( Eocell ) = 2.462 VThe cell potential ( Ecell ) = 2.36 V [ Al3+ ]…

Q: A galvanic cell is set up with iron and aluminum half-cells, according to the unbalanced reaction…

A: We can calculate Ecell by using Nerst equation

Q: When the Hg2+ concentration is 1.25 M, the observed cell potential at 298K for an electrochemical…

A: We will first find the Eo,cell using the formula given below. Then the Eo of anode and cathode are…

Q: When the Pb2* concentration is 1.00 M, the observed cell potential at 298K for an electrochemical…

A: It's a multiple question type and according to the guidelines of Bartleby, we are supposed to answer…

Q: Refer to the galvanic cells made from different combinations of the half-cells containing…

A: ∆G =-nFE , Where n is number of shared electrons . F is Faraday constant E is cell potential.

Q: In the box on the diagram attached, what is the solid from the reaction, M(s) or X(s), that is used…

A: M2+ + 2e- ----> M(s) ; E° = -0.35 V X3+ + 3e- ----> X(s) ; E° = +1.80 V In the box…

Q: Mn2+ concentration?

Q: Calculate the time needed to operate an electrolytic cell to plate 0.64 g of Z that is running at…

Q: Using the voltaic cell below: A) Write the equation for this cell. B) Calculate standard cell…

A: A) The 2 possible half reactions are 1) Al3+ (aq) + 3 e- -------> Al (s) E0 =…

Q: eded for this question. When the Hg 2+ concentration is 1.41 M, the observed cell potential at 298 K…

A: Step 1: The reaction Zn(s)+Hg2+→Zn2+ + Hg(l) Anode reaction: Zn(S)→Zn2+ + 2e-Cathode reaction:…

Q: A Cu>Cu2+ concentration cell has a voltage of 0.22 V at 25°C.The concentration of Cu2+ in one of…

A: Given , T= 25°C E°cell = 0. 22 V Let us assume the concentration of…

Q: Salt bridge A concentration cell similar to the one shown is composed of two Cu electrodes and…

A: The Nernst equation is given as :

Q: When [Hg2+] = 1.26 M, the observed cell potential at 298 K for an electrochemical cell with the…

A: Data given: The concentration of [Hg2+] = 1.26 M Observed cell potential, Ecell = 3.320 V Cell…

Q: Similar pairs) 2+ 21.27 A voltaic cell is constructed with an Sn/Sn²* half-cell and a ZnZn*…

A: Introduction : Volatic cells is a device used to convert the chemical energy into electrical energy…

Q: Consider the Nernst equation. A voltaic cell is constructed that uses the following reaction and…

A: No of electrons = 2 2nd term of nernst equation =?

Q: <Chapter 19 Exercise 19.78 - Enhanced -with Feedback A Cu/Cu concentration cell has a voltage of…

Q: Determine the FALSE statement regarding a concentration cell based on H" (aq). Assume that the…

A: Option d is incorrect.

Q: What is the calculated value of the cell potential at 298K for an electrochemical cell with the…

Q: two half-cells are used to have a galvanic cell: Ni|Ni+2 and Au| Au+3. determine the ff

A: The standard emf of a Galvanic cell is determined by using the formula E°cell = E°cathode - E°anode…

Q: Which of the following statements is FALSE? Ni(s) → Ni2+ + 2 e− Group of answer choices The…

A: To solve this problem we use Nernst equation Ecell = EMF of the cell E°cell = EMF of the cell at…

Q: A Cu/Cu?+ concentration cell has a voltage of 0.20 V at 25 °C. The concentration of Cu+ in one of…

A: [Cu2+ unknown] = 1.21 x 10-4 M

Q: When the Cu2+ concentration is 1.27 M, the observed cell potential at 298K for an electrochemical…

A: Step by step solution are below

Q: When the Cu²+ concentration is 1.02 M, the observed cell potential at 298K for an electrochemical…

Q: Hw.4.

Q: Refer to the galvanic cells made from different combinations of the half-cells containing…

A: A ) 2 X + 3Y+ ==> 2X3+ + 3 Y E°= 1.87 C) Z + Y2+ ==> Z2+ + Y E° = 0.94

Q: Consider an electrochemical cell with the following half-cells: Pb2+(aq,0.01M)|Pb(s) and…

A: Kindly get the answer given below.

Q: alculate the value of the potential for the following electrochemical cell under the conditions…

A: It is based on the application of Nernst equation Here we are required to find the cell potential…

Q: What is the calculated value of the cell potential at 298K for an electrochemical cell with the…

A: Cell potential is calculated using Nernst Equation. Given: [Hg2+] = 1.24 x 10-4 M…

Q: When the Pb2+ concentration is 1.16 M, the observed cell potential at 298K for an electrochemical…

A: Given, [Pb2+] = 1.16 M And Ecell = 0.732 V E° of Pb2+/Pb = -0.13 V and that of Zn2+/Zn = -0.76…

Q: An electrochemical cell has the following half cell information: Cathode E°=2.01 V anode E°= 0.68…

A: Answer:- This question is answered by using the simple concept of calculation of standard cell…

Q: What's the concentration of Zn2+ in the other half-cell,assuming the concentration in the unknown…

A: The concentration of Zn2+ in the other half-cell is to be calculated.

Q: What is K for the spontaneous reaction 3 Zn2+ + 2 Al (s) ↔ 2 Al3+ + 3 Zn(s) ? What potential…

A: The ratio of concentration of products to the concentration of reactants raised to their…

Q: For the galvanic (voltaic) cell Cu(s) + Mn²⁺(aq) ⟶ Cu²⁺(aq) + Mn(s) (E° = 0.60 V at 25°C), what is E…

Q: When the Cu2+ concentration is 1.00 M, the observed cell potential at 298K for an electrochemical…

Question

A concentration cell is
constructed using two Pb/Pb4+
half-cells. If the [Pb4+] in one of
the half-cells is 6.74 M, what
would it have to be in the other
half cell for the concentration
cell to produce exactly 0.0192 V?
Assume the cell operates at
25°C.
Answer:
M

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

A Cu/Cu2+ concentration voltage of 0.24 Vat 25 °C. The cell has a concentration of Cu2+ in one of the half-cells is 1.4×10-³ M. What is the concentration of Cu2+ in the other half-cell? (Assume the concentration in the unknown cell to be the lower of the two concentrations.) [Cu2+] =?
A concentration cell consists of two Sn/Sn2+ half-cells. The electrolyte in compartment A is 0.13M Sn(NO3)2. The elec-trolyte in B is 0.87 MSn(NO3)2. Which half-cell houses thecathode? What is the voltage of the cell?
When the Hg+ concentration is 1.44 M, the observed cell potential at 298 K for an electrochemical cell with the following reaction is 1.717 V. What is the Zn2+ concentration? Hg (aq) + Zn(s) → Hg(1) + Zn²+ (aq) Zn M
When the Hg2+ concentration is 1.11×10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 1.916V. What is the Mn2+ concentration?Hg2+(aq) + Mn(s) Hg(l) + Mn2+(aq)
When the Cu²+ concentration is 4.28x104 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 0.999V. What is the Zn2+ concentration? Cu2+ (aq) + Zn(s) Cu(s) + Zn²+ (aq) Answer: M
A concentration cell is constructed in which the concentrations differ in the two half-cells. The cell consists of a Au (aq, 3.20×10³ M)| Au(s) half-cell connected to a Au* (aq, 0.710 M) Au(s) half-cell. Determine which half-cell will be the cathode compartment and calculate the cell voltage. The Au concentration in the cathode compartment will be: a. 3.20×10-³ M b. 0.710 M Ecell = V
Use the References to access important values if needed for this question. What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the Cu²+ concentration is 6.63x10-4 M and the Mn²+ concentration is 1.47 M ? Cu²*(aq) + Mn(s)→ Cu(s) + Mn²+*(aq) Answer: V The cell reaction as written above is spontaneous for the concentrations given: true false Submit Answer Try Another Version 3 item attempts remaining
In each voltaic cell, one half-cell contains a 1.0 M Fe1NO3221aq2 solution with a Fe electrode. The contents of the other half-cells are as follows:Cell 1: a 1.0 M CuCl21aq2 solution with a Cu electrodeCell 2: a 1.0 M NiCl21aq2 solution with a Ni electrodeCell 3: a 1.0 M ZnCl21aq2 solution with a Zn electrodeIn which voltaic cell(s) does iron act as the anode?
4
A voltaic cell is constructed from an Ni 2+1aq2 - Ni1s2 half-cell and an Ag+1aq2 - Ag1s2 half-cell. The initial concentration of Ni 2+1aq2 in the Ni 2+ - Ni half-cell is 3Ni 2+4 = 0.0100 M. The initial cell voltage is +1.12 V.Will the concentration of Ni 2+1aq2 increase or decrease as the cell operates?
A voltaic cell is constructed in which the anode is a Fe|Fe2+ half cell and the cathode is a Ag|Ag+ half cell. The half-cell compartments are connected by a salt bridge.
When the Cu2+ concentration is 2.68x10-4 M, the observed cell potential at 298K for an electrochemical cell with the following reaction is 2.600V. What is the Mg2+ concentration? Cu2+(aq) + Mg(s)→ Cu(s) + Mg2+(aq) Answer: | M