A compound is 63.68% carbon, 12.38% nitrogen, 9.80% hydrogen, and 14.14% oxygen. Determine its empirical formula. View Available Hint(s) O C6H₁1 NO O Na₂C6H₁1 NO O C3H55N0.500.5 O C12H22N₂0₂ Submit
A compound is 63.68% carbon, 12.38% nitrogen, 9.80% hydrogen, and 14.14% oxygen. Determine its empirical formula. View Available Hint(s) O C6H₁1 NO O Na₂C6H₁1 NO O C3H55N0.500.5 O C12H22N₂0₂ Submit
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:A compound is 63.68% carbon, 12.38% nitrogen, 9.80% hydrogen, and 14.14% oxygen. Determine its empirical formula.
► View Available Hint(s)
O C6H11NO
O Na₂C6H₁1NO
O C3H5.5 No.500.5
O C12H22N2O2
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Transcribed Image Text:Determine the empirical and molecular formulas of
each of the following substances.
▼
▼
Part A
Styrene, a compound substance used to make Styrofoam cups and insulation, contains
92.3% C and 7.7% H by mass and has a molar mass of 104 g/mol.
Express your answers as chemical formulas separated by a comma.
Submit
Part B
ΑΣΦ
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?
Caffeine, a stimulant found in coffee, contains 49.5% C, 5.15% H, 28.9% N, and 16.5
%O by mass and has a molar mass of 195 g/mol.
Express your answers as chemical formulas separated by a comma.
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Step 1: Determine the empirical and molecular formulas of the compounds from the given data:
VIEWStep 2: (i) Calculation for empirical formula:
VIEWStep 3: A. Calculation for empirical formula:
VIEWStep 4: A. Calculation for molecular formula:
VIEWStep 5: B. Calculation for empirical formula:
VIEWStep 6: B. Calculation for molecular formula:
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