A compound has the following percent compositions. Find the empirical formula of this compound. 52.13% C, 13.15 % H and 34.72 % O 2. A compound has a molar mass of 86.18 g/mol, and the following percent compositions. Find BOTH the molecular formula and the empirical formula 83.62% for carbon and 16.38% for hydrogen.

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A: Empirical formula is a formula of a compound which show the simplest whole number ratio between the…

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Q: Molar Masses A = 12.98 D = 13.43– X = 22.40–2 E = 19.26 Z = 4.032 mole mole G = 16.42 mole mole A…

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A: Given,Percent of B in the compound = 40.28 %Percent of N in the compound = 52.20 %Percent of H in…

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Q: Shown below is the % composition of a compound made entirely of C, H, N, and O. This compound has a…

A: Consider the given % Composition of the elements is as follows; C = 40.32%H = 7.83%O = 35.80%N =…

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A: Since the compound contains only C, H and O. Hence assuming the empirical formula of the compound is…

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A: Element % K 24.74 Mn 34.76 O 40.50

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A: Percentage Composition of compound Carbon = 70.02% Hydrogen = 3.36% Oxygen = 26.64% Empirical…

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A: Given C = 76.0%, H = 12.7% and O = 11.3%.

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Q: 2. Find the empirical formula of a compound that contains 53.70% iron and 46.30% sulfur.

A: 2. Let the compound is 100g  So we have 100% = 100g or 1% = 1g So, Iron(Fe) = 53.70% = 53.70 g and…

Q: Chemical analysis shows that a compound is composed of 34.3% (by mass) sodium (Na), 17.9% carbon (C)…

A: Given: The % composition of Na= 34.3% The % composition of C= 17.9% The % composition of O= 47.8%

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.