A composite shaft consists of a brass sleeve securely bonded to half steel shaft, fixed at end A as shown in Figure 1. The brass sleeve and steel shaft have a modulus rigidity Gb = 40 GPa and Gs = x0 GPa. The length of the assembly is L = 400 mm. The outer diameters of the shaft and sleeve are d1 = 70 mm and d2 = 90 mm, respectively. Given the shear stress of brass is τb = 70 MPa and shear stress of steel is τs = 110 MPa. [Note: x value - Use the last non-zero digit from your group number. If the group number is zero, use the second last digit instead. For example, if your group number is 5, your x value is 5 and Gs = 50 GPa; if your group number is 10, your x value is 1 and Gs = 10 GPa.] In this situation, Group number is 2. 1) Derive the equation of internal torques of section AB, i.e. torque for brass sleeve Tb and torque for steel shaft Ts in terms of T using the compatibility equation. [Note: Mention your matric number and corresponding Gs value.] 2) Formulate the equation of angle of twist at end C with respect to A in terms of T.
A composite shaft consists of a brass sleeve securely bonded to half steel shaft, fixed at end A as shown in Figure 1. The brass sleeve and steel shaft have a modulus rigidity Gb = 40 GPa and Gs = x0 GPa. The length of the assembly is L = 400 mm. The outer diameters of the shaft and sleeve are d1 = 70 mm and d2 = 90 mm, respectively. Given the shear stress of brass is τb = 70 MPa and shear stress of steel is τs = 110 MPa. [Note: x value - Use the last non-zero digit from your group number. If the group number is zero, use the second last digit instead. For example, if your group number is 5, your x value is 5 and Gs = 50 GPa; if your group number is 10, your x value is 1 and Gs = 10 GPa.] In this situation, Group number is 2. 1) Derive the equation of internal torques of section AB, i.e. torque for brass sleeve Tb and torque for steel shaft Ts in terms of T using the compatibility equation. [Note: Mention your matric number and corresponding Gs value.] 2) Formulate the equation of angle of twist at end C with respect to A in terms of T.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
A composite shaft consists of a brass sleeve securely bonded to half steel shaft, fixed at
end A as shown in Figure 1. The brass sleeve and steel shaft have a modulus rigidity Gb
= 40 GPa and Gs = x0 GPa. The length of the assembly is L = 400 mm. The outer
diameters of the shaft and sleeve are d1 = 70 mm and d2 = 90 mm, respectively. Given
the shear stress of brass is τb = 70 MPa and shear stress of steel is τs = 110 MPa.
[Note: x value - Use the last non-zero digit from your group number. If the group number
is zero, use the second last digit instead. For example, if your group number is 5, your x
value is 5 and Gs = 50 GPa; if your group number is 10, your x value is 1 and Gs = 10
GPa.]
In this situation, Group number is 2.
1) Derive the equation of internal torques of section AB, i.e. torque for brass sleeve
Tb and torque for steel shaft Ts in terms of T using the compatibility equation.
[Note: Mention your matric number and corresponding Gs value.]
2) Formulate the equation of angle of twist at end C with respect to A in terms of T.
![A composite shaft consists of a brass sleeve securely bonded to half steel shaft, fixed at
end A as shown in Figure 1. The brass sleeve and steel shaft have a modulus rigidity Gp
Brass sleeve
d; = 90mm
di = 70mm
Steel shaft
= 40 GPa and Gs = x0 GPa. The length of the assembly is L = 400 mm. The outer
diameters of the shaft and sleeve are di = 70 mm and d2 = 90 mm, respectively. Given
the shear stress of brass is Tb = 70 MPa and shear stress of steel is Ts = 110 MPa.
[Note: x value - Use the last non-zero digit from your group number. If the group number
B
1 = 200mm
L = 200mm
is zero, use the second last digit instead. For example, if your group number is 5, your x
value is 5 and G = 50 GPa; if your group number is 10, your x value is 1 and Gs = 10
GPa.]
Figure 1: A compound of shaft consisting brass sleeve and steel shaft.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6fb41708-6219-404f-b095-11a4f0a684db%2F8131a9ab-ba64-47ac-9c0d-cadc23d6c48f%2Fhqlq15s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A composite shaft consists of a brass sleeve securely bonded to half steel shaft, fixed at
end A as shown in Figure 1. The brass sleeve and steel shaft have a modulus rigidity Gp
Brass sleeve
d; = 90mm
di = 70mm
Steel shaft
= 40 GPa and Gs = x0 GPa. The length of the assembly is L = 400 mm. The outer
diameters of the shaft and sleeve are di = 70 mm and d2 = 90 mm, respectively. Given
the shear stress of brass is Tb = 70 MPa and shear stress of steel is Ts = 110 MPa.
[Note: x value - Use the last non-zero digit from your group number. If the group number
B
1 = 200mm
L = 200mm
is zero, use the second last digit instead. For example, if your group number is 5, your x
value is 5 and G = 50 GPa; if your group number is 10, your x value is 1 and Gs = 10
GPa.]
Figure 1: A compound of shaft consisting brass sleeve and steel shaft.
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