A composite beam is fabricated by bolting two 2-in.-wideby 12-in.-deep timber planks to the sides of a 0.4-in. by 12-in.steel plate. The moduli of elasticity of the timber and thesteel are 1680 ksi and 29900 ksi, respectively. The simplysupported beam spans a distance of 18 ft and carries twoconcentrated loads P, which are applied as shown. AssumeLAB=LCD= 5 ft, LBC = 8 ft, b = 2 in., d = 12 in. and t = 0.4 in.(a) Determine the maximum bending stresses o,, Osproduced in the timber planks and the steel plate if P= 3.1 kips.(b) Assume that the allowable bending stresses of the timberand the steel are 1190 psi and 19700 psi, respectively.Determine the largest acceptable magnitude forconcentrated loads P. (You may neglect the weight of thebeam in your calculations.)ALABPBLBCsykbbCross sectionCLCDD Answers:(a) ot(b) P=iiksi.ksi, oskips.

Answered: Image /qna-images/answer/f86e6eab-ebec-4515-beb7-7c2bda2d7815.jpg

A composite beam is fabricated by bolting two 2-in.-wide by 12-in.-deep timber planks to the sides of a 0.4-in. by 12-in. steel plate. The moduli of elasticity of the timber and the steel are 1680 ksi and 29900 ksi, respectively. The simply supported beam spans a distance of 18 ft and carries two concentrated loads P, which are applied as shown. Assume LAB=LCD= 5 ft, LBC = 8 ft, b = 2 in., d = 12 in. and t = 0.4 in. (a) Determine the maximum bending stresses 0₁, 0, produced in the timber planks and the steel plate if P = 3.1 kips. (b) Assume that the allowable bending stresses of the timber and the steel are 1190 psi and 19700 psi, respectively. Determine the largest acceptable magnitude for concentrated loads P. (You may neglect the weight of the beam in your calculations.) LAB B LBC F Lodko b b 18 C LCD D

A composite beam is fabricated by bolting two 2-in.-wide by 12-in.-deep timber planks to the sides of a 0.4-in. by 12-in. steel plate. The moduli of elasticity of the timber and the steel are 1680 ksi and 29900 ksi, respectively. The simply supported beam spans a distance of 18 ft and carries two concentrated loads P, which are applied as shown. Assume LAB=LCD= 5 ft, LBC = 8 ft, b = 2 in., d = 12 in. and t = 0.4 in. (a) Determine the maximum bending stresses 0₁, 0, produced in the timber planks and the steel plate if P = 3.1 kips. (b) Assume that the allowable bending stresses of the timber and the steel are 1190 psi and 19700 psi, respectively. Determine the largest acceptable magnitude for concentrated loads P. (You may neglect the weight of the beam in your calculations.) LAB B LBC F Lodko b b 18 C LCD D

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter9: Composite Construction

Section: Chapter Questions

Problem 9.1.3P

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Concept explainers

Composite Construction

Composite construction is the construction of structures in which two or more materials are used. Regarding structural engineering, composite construction is a construction where two materials are bound together in a technical manner such that both the materials act as a single unit to carry and transfer the load. The motives of composite construction are to increase the structural strength, make structures more aesthetic, and provide a sustainable environment.

Question

A composite beam is fabricated by bolting two 2-in.-wide
by 12-in.-deep timber planks to the sides of a 0.4-in. by 12-in.
steel plate. The moduli of elasticity of the timber and the
steel are 1680 ksi and 29900 ksi, respectively. The simply
supported beam spans a distance of 18 ft and carries two
concentrated loads P, which are applied as shown. Assume
LAB=LCD= 5 ft, LBC = 8 ft, b = 2 in., d = 12 in. and t = 0.4 in.
(a) Determine the maximum bending stresses o,, Os
produced in the timber planks and the steel plate if P
= 3.1 kips.
(b) Assume that the allowable bending stresses of the timber
and the steel are 1190 psi and 19700 psi, respectively.
Determine the largest acceptable magnitude for
concentrated loads P. (You may neglect the weight of the
beam in your calculations.)
A
LAB
P
B
LBC
syk
b
b
Cross section
C
LCD
D

Answers:
(a) ot
(b) P=
i
i
ksi.
ksi, os
kips.

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