a) Complete the missing sequence numbers (SEQ), acknowledgment mumbers (ACK), and segment length (LEN) in the following TCP connection. We assame: • No timeouts occur at the receiver. • The sender starts the timer at tl. • The connection is full duplex (bi-directional data flow in same connection). • The sender and the receiver have always data to transmit. There are no delayed acknowledgements at the sender or the receiver. Sender Receiver 11 SEO 100 ACK ALEN40. 12 SEO B ACK=20 LENC A B. SEQ:D ACK E LEN SEOE ACK=G LENE 13 „SEQ=HACK=LEN 14 SEQ:140 ACKJLEN=20

a) Complete the missing sequence numbers (SEQ), acknowledgment mumbers (ACK), and segment length (LEN) in the following TCP connection. We assame: • No timeouts occur at the receiver. • The sender starts the timer at tl. • The connection is full duplex (bi-directional data flow in same connection). • The sender and the receiver have always data to transmit. There are no delayed acknowledgements at the sender or the receiver. Sender Receiver 11 SEO 100 ACK ALEN40. 12 SEO B ACK=20 LENC A B. SEQ:D ACK E LEN SEOE ACK=G LENE 13 „SEQ=HACK=LEN 14 SEQ:140 ACKJLEN=20

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Does this make sense to you, or do you believe it to be incorrect? Consider the most recent SampleRTT on a TCP connection to be one second. In order for the connection to be deemed active and functioning, the current TimeoutInterval value must be greater than one second.
TCP is a sliding window protocol. This means. а. there can be more than one segment "in flight" (sent but no ACK has been received) at a time. O b. the TCP retransmission timer slides up as ACKS are received. O c. there can only be one segment outstanding (sent but no ACK has been received) at at time.
Explain why in TCP we are using the credit scheme instead of the slighting window. Point out what the key difference(s) is(are).
If there is wide variation in the TCP segment size , it is natural to organize the buffers as a pool of fixed-sized buffers, with one segment per buffer TRUE OR FALSE
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Consider a TCP connection with the following parameters: a) Initial ssthreshold = 8 b) Round Trip Time (RTT) = 10 milliseconds c) Retransmission Timeout period = 40 milliseconds d) Segment size = 2700 bytes The TCP connection was used to transfer 19 data segments, numbered 1 through 19. While sending the segments, data segment 10 was lost the first time it was sent (but arrived at the receiver properly upon being retransmitted). There were no other segment losses apart from the aforementioned. Assume that data segments received out-of-order are buffered at the receiver. What is the average throughput obtained in sending all the data segments (in bytes/sec)? Draw a diagram to show the transmission of the segments in detail.
Is this an accurate or wrong statement? For simplicity, let us assume that the most recent SampleRTT on a TCP connection is one second. The current TimeoutInterval value for the connection must be greater than one second in order to maintain the connection.
Is this the right answer or the wrong answer? Assume that the most recent SampleRTT for a TCP connection is one second. The TimeoutInterval setting for the connection must now be set to a value that is greater than one second.
Is this correct or incorrect? Assume that on a TCP connection, the most recent SampleRTT is 1 second. The current TimeoutInterval value for the connection must be larger than one second.
TCP congestion control example. Consider the figure below, where a TCP sender sends 8 TCP segments at t = 1, 2, 3, 4, 5, 6, 7, 8. Suppose the initial value of the sequence number is 0 and every segment sent to the receiver each contains 100 bytes. The delay between the sender and receiver is 5 time units, and so the first segment arrives at the receiver at t = 6. The ACKs sent by the receiver at t = 6, 7, 8, 10, 11, 12 are shown. The TCP segments (if any) sent by the sender at t = 11, 13, 15, 16, 17, 18 are not shown. The segment sent at t=4 is lost, as is the ACK segment sent at t=7. TCP sender t=1 T t=2 t=3 t=4+ t=5- t=6+ t=11 t=12 t=13 t=14 t=15 t=16 t=17 t=18 I data segment data segment data segment data segment data segment data segment data segment data segment ACK ACK ACK ACK ACK ACK Ty A A V V htt TCP receiver t=6 t=7 t=8 t=9 t=10 t=11 t=12 t=13 What does the sender do at t=17? You can assume for this question that no timeouts have occurred.
Can you confirm or deny that this is the case? Assume that the most recent SampleRTT on a TCP connection is 1 second. It's not possible to have a connection with a TimeoutInterval less than one second.
Consider a TCP connection with the following parameters: a) Initial ssthreshold = 4 segmentsb) Round Trip Time (RTT) = 10 millisecondsc) Timeout period = 40 millisecondsd) Segment size = 3900 bytesThe TCP connection was used to transfer 17 data segments. While sendingthe segments, data segment 7 and data segment 15 were lost the first timethey were sent (but arrived at the receiver properly when retransmitted).There were no other segment losses apart from the aforementioned. Assumethat data segments received out-of-order are buffered at the receiver. Whatis the average throughput obtained in sending all the data segments (inbytes/sec) including draw a diagram to show the communication process in detail.