A company offers its clients bonds that mature after different numbers of years. The cumulative distribution function of is given and the number of years to maturity for a randomly particular bond, is ft=
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- A company offers its clients bonds that mature after different numbers of years. The cumulative distribution
function of is given and the number of years to maturity for a randomly particular bond, is
ft=
| o | x<2 |
| o.3 | 2<=x<4 |
| o.6 | 4<=x<6 |
| o.8 | 6<=x<8 |
| 1 | x>=8 |
Find
1) p(x=6)
2) p(x>2)
3) p(2.2<x<5)
Step by step
Solved in 3 steps with 3 images
- Please see attached image...Consider an auto insurance portfolio where the number of accidents follows a Poisson distribution with parameter λ= 1000. Suppose the damage sizes for separate accidents are i.i.d. (independent identically distributed) r.v.'s having an exponential distribution with a mean of $2500. Each policy involves a deductible of $500. Let N₁ be the number of accidents that result in claims, and N₂ be the number of accidents that do not result in claims. Answer the following questions 1-5. Q1 Are N₁, N₂ dependent? Q2 Depends on a situation, No Yes What is the name of the distributions of N₁, №₂? O Marked Poisson Gamma Exponential Compound PoissonPage 348 5.3.14
- The following function is a cumulative distribution function. x < -10 0.1510Explain the steps if you can5% Coupon 10% Coupon 15% Coupon Average Yield-to-Maturity of 5 Years to Maturity Bonds . 9.01% 9.03% Average Yield-to-Maturity of 8 Years to Maturity Bonds 9.47% . 9.28% I am having trouble finding the missing value for Maturity 5 through linear interpolation. YTM, x = 9.01% + [ (15-10)/(15-5) * (9.03%-x) ] I saw this solution but I have no idea when they got the answer 8.99% from that. Please helpThe US divorce rate has been reported as 3.6 divorces per 1000 population. Assuming that this rate applies to a small community of just 500 people and it’s Poisson distributed, and that x = the number of divorces in this community during the coming year, determine the following : a. E(x) b. P(x=1) c. P(x=4) d. P(x6) e. P(2x5)1 Events X and Y are such that P(x)=0.35 and P(x or y)=0.80. Given that X and Y are independent and non‐mutually exclusive, determine p(y). Give your finalanswer as a percentage to two decimal places.23. Find the cumulant generating function of gamma distribution and obtain various cumulants.Please answer exercise 2öalg älbäi Q3) An investment firm offers its customers municipal bonds that mature after varying numbers of years. Given that the cumulative distribution function of T, the number of years to maturity for a randomly selected bond, is as shown below, Find * (P(0.4s ts6 0, 0 < t<1 1/28, 4/28, 6/28, 7/28, 8/28, 15.2.1 The conditional probability distribution of Y given X = x is fy.0) = xe-y for y> 0, and the marginal probability distribution of X is a continuous uniform distribution over 0 to 10. a. Graph fyv) = xe¬w for y > 0 for several values of x. Determine: b. P(Y < 2|X = 2) d. E(Y |X = x) f. fr(y) c. E(Y | X = 2) e. fxy(x, y)SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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